下面是代码
$(document).ready(function() {
$('#st').change(function(){
var st = $('#st').val(); // start time Format: '9:00 PM'
var et = $('#et').val(); // end time Format: '11:00 AM'
//how do i compare time
if(st > et)
{
alert('end time always greater then start time');
}
});
});如果我有如下时间范围
Start Time Range (listbox) = 12:00 AM To 11:59PM
End Time Range (listbox) = 12:00 AM To 11:59PM那么如何验证开始时间小于结束时间或结束时间大于开始时间
Start-time < End-time OR End-time > St-time考虑js代码中的时间格式,由于时间格式无法实现差分逻辑
Format: '9:00 AM'
Format: '5:00 PM'发布于 2013-01-15 21:31:32
这是我在调查之后得到的。
如果时间格式为 in 12 Hour-Time或24 Hour-Time,则最佳做法。
//start time
var start_time = $("#start_time").val();
//end time
var end_time = $("#end_time").val();
//convert both time into timestamp
var stt = new Date("November 13, 2013 " + start_time);
stt = stt.getTime();
var endt = new Date("November 13, 2013 " + end_time);
endt = endt.getTime();
//by this you can see time stamp value in console via firebug
console.log("Time1: "+ stt + " Time2: " + endt);
if(stt > endt) {
$("#start_time").after('<span class="error"><br>Start-time must be smaller then End-time.</span>');
$("#end_time").after('<span class="error"><br>End-time must be bigger then Start-time.</span>');
return false;
}发布于 2012-06-28 20:49:28
您必须将字符串转换为可以在时间上进行比较的值。Date.parse会派上用场,不过您也需要传递日期。因为你只关心时间,所以对两个都使用相同的假日期。
if(Date.parse("1-1-2000 " + st) > Date.parse("1-1-2000 " + et)) {发布于 2015-01-23 16:35:47
您甚至可以尝试以下jquery规则:jQuery.validator.addMethod
jQuery.validator.addMethod("timeValidator",
function (value, element, params) {
var val = new Date('1/1/1991' + ' ' + value);
var par = new Date('1/1/1991' + ' ' + $(params).val());
if (!/Invalid|NaN/.test(new Date(val))) {
return new Date(val) > new Date(par);
}
return isNaN(val) && isNaN(par)
|| (Number(val) > Number(par));
}, 'End Time must be greater than Start Time.');您可以调用规则:
$("#txtToTime").rules('add', { timeValidator: "#txtFromTime" });https://stackoverflow.com/questions/11244943
复制相似问题