CLPlacemark -状态缩写？

Question

我想知道是否有可能从CLPlacemark获取州缩写？

在苹果的CLPlacemark参考中，它写道：

administrativeArea与地标关联的州或省。(只读)@ property (非原子，只读) NSString *administrativeArea讨论如果地点标记位置是苹果的总部，则此属性的值将是字符串“CA”或“California”。

但每当我使用它时，我只能得到完整的州(即加利福尼亚州)，而不是缩写(即CA)。有人能帮我吗？

Answer 1

对于其他需要解决此问题的人，我为CLPlacemark创建了一个category类，它返回简短的状态字符串。您所需要做的就是调用myPlacemark shortState

CLPlacemark+ShortState.h

#import <CoreLocation/CoreLocation.h>
#import <Foundation/Foundation.h>

@interface CLPlacemark (ShortState)

- (NSString *)shortState;

@end

CLPlacemark+ShortState.m

#import "CLPlacemark+ShortState.h"

@interface CLPlacemark (ShortStatePrivate)

- (NSDictionary *)nameAbbreviations;

@end

@implementation CLPlacemark (ShortState)

- (NSString *)shortState {

    NSString *state = [self.administrativeArea lowercaseString];

    if (state.length==0)
        return nil;

    return [[self nameAbbreviations] objectForKey:state];

}

- (NSDictionary *)nameAbbreviations {

    static NSDictionary *nameAbbreviations = nil;

    static dispatch_once_t onceToken;
    dispatch_once(&onceToken, ^{

        nameAbbreviations = [NSDictionary dictionaryWithObjectsAndKeys:
                             @"AL",@"alabama",
                             @"AK",@"alaska",
                             @"AZ",@"arizona",
                             @"AR",@"arkansas",
                             @"CA",@"california",
                             @"CO",@"colorado",
                             @"CT",@"connecticut",
                             @"DE",@"delaware",
                             @"DC",@"district of columbia",
                             @"FL",@"florida",
                             @"GA",@"georgia",
                             @"HI",@"hawaii",
                             @"ID",@"idaho",
                             @"IL",@"illinois",
                             @"IN",@"indiana",
                             @"IA",@"iowa",
                             @"KS",@"kansas",
                             @"KY",@"kentucky",
                             @"LA",@"louisiana",
                             @"ME",@"maine",
                             @"MD",@"maryland",
                             @"MA",@"massachusetts",
                             @"MI",@"michigan",
                             @"MN",@"minnesota",
                             @"MS",@"mississippi",
                             @"MO",@"missouri",
                             @"MT",@"montana",
                             @"NE",@"nebraska",
                             @"NV",@"nevada",
                             @"NH",@"new hampshire",
                             @"NJ",@"new jersey",
                             @"NM",@"new mexico",
                             @"NY",@"new york",
                             @"NC",@"north carolina",
                             @"ND",@"north dakota",
                             @"OH",@"ohio",
                             @"OK",@"oklahoma",
                             @"OR",@"oregon",
                             @"PA",@"pennsylvania",
                             @"RI",@"rhode island",
                             @"SC",@"south carolina",
                             @"SD",@"south dakota",
                             @"TN",@"tennessee",
                             @"TX",@"texas",
                             @"UT",@"utah",
                             @"VT",@"vermont",
                             @"VA",@"virginia",
                             @"WA",@"washington",
                             @"WV",@"west virginia",
                             @"WI",@"wisconsin",
                             @"WY",@"wyoming",
                             nil];
    });

    return nameAbbreviations;
}

@end

Answer 2

我认为你不能得到州的缩写，但是你可以为这个创建你自己的类。

列出所有状态( states standards)

• compare
• 并返回缩写

代码..

StateAbbreviation类

StateAbbreviation.h

@interface StateAbbreviation : NSString {

}

+ (NSString *)allStates:(int)index;
+ (NSString *)abbreviatedState:(NSString *)strState;

@end

StateAbbreviation.m

@implementation StateAbbreviation
+ (NSString *)allStates:(NSString *)strState {
   // Remove all space on the string
   strState = [strState stringByReplacingOccurrencesOfString:@" " withString:@""];
   //Sample states
   NSArray *states = [[NSArray alloc] initWithObjects:
                       @"ALABAMA",                      
                       @"ALASKA",        //AK
                       @"AMERICANSAMOA", //AS
                       @"ARIZONA",       //AZ
                       @"ARKANSAS",      //AR
                       @"CALIFORNIA",    //CA
                       nil];
  NSUInteger n = [states indexOfObject:strState];
  if (n > [states count] - 1) {
     strAbbreviation = @"NOSTATE";
  }
  else {
     strAbbreviation =[self abbreviatedState:n];
  }
  [states release];
  return strAbbreviation;
}

+ (NSString *)abbreviatedState:(int)index {
    NSArray *states = [[NSArray alloc] initWithObjects:
                       @"AL",
                       @"AK",
                       @"AS",
                       @"AZ",
                       @"AR",
                       @"CA",
                       nil];
       NSString *strAbbreviation = [states objectAtIndex:index];
       [states release];
       return strAbbreviation;
}
@end

当你调用这个类时，它应该是这样的

NSString *upperCase = [@"California" uppercaseString]; // California could be from (NSString *)placemark.administrativeArea;
NSString *abbr = [StateAbbreviation allStates:upperCase];
NSLog(@"%@", abbr); // Result should be CA

这只是你可以研究所有状态的样本，就像这样，states and their abbreviations也像这样

Answer 3

我相信文档是不正确的。administrativeArea将始终返回美国各地区的全州名称。要获得州缩写，您很可能需要创建一个字典查找表，以便搜索关键字"California“将返回值"CA”。