我有一个通过控制器处理图像请求的SimpleDraweeView:
Postprocessor redMeshPostprocessor = new BasePostprocessor() {
@Override
public String getName() {
return "redMeshPostprocessor";
}
@Override
public CloseableReference<Bitmap> process(
Bitmap sourceBitmap,
PlatformBitmapFactory bitmapFactory) {
//custom processing on the bitmap and returning it
}
};
ImageRequest request = ImageRequestBuilder.newBuilderWithSource(Uri.parse(coverImage))
.setPostprocessor(redMeshPostprocessor)
.build();
PipelineDraweeController controller = (PipelineDraweeController)
Fresco.newDraweeControllerBuilder()
.setImageRequest(request)
.setOldController(iv_cover.getController())
// other setters as you need
.build();
iv_cover.setController(controller);然后,我想通过简单地说一句话来更改SimpleDraweeView上的图像:
iv_cover.setImageURI(Uri.parse(url));问题是,当加载第二个图像时,SimpleDraweeView会在瞬间显示占位符。如何避免这种情况?希望2个图像之间的过渡是无缝和平滑的。谢谢!
发布于 2016-05-27 00:53:59
您可以这样做:
PipelineDraweeController controller = (PipelineDraweeController)
Fresco.newDraweeControllerBuilder()
.setLowResImageRequest(previousRequest)
.setImageRequest(newRequest)
.setOldController(iv_cover.getController())
.build();
iv_cover.setController(controller);这应该会给你想要的行为。
https://stackoverflow.com/questions/36869182
复制相似问题