我试图创建一个页面,将吐出一个用户的发票。我在检索特定用户的发票时遇到了问题。控制器中的功能和设置$id有问题。我不确定如何将其设置为当前用户。
下面是我的函数中的相关代码
public function payInvoice(){
$this->set('title_for_layout', 'Pay Invoice');
$this->set('stylesheet_used', 'homestyle');
$this->set('image_used', 'eBOXLogoHome.jpg');
$this->layout='home_layout';
$userid = $this->Auth->user('id');
$this->set('Invoices', $this->Invoice->findByBiller($userid));
}这是我的观点包含的答案:
<table width="100%" border="1">
<tr>
<th>Biller</th>
<th>Subject</th>
<th>Date</th>
<th>Action</th>
</tr>
<?php foreach($Invoices as $invoice):?>
<tr>
<td align='center'><?php echo $this->Html->link($Invoices['Invoice']['to'],
array('action' => 'viewInvoice', $Invoices['Invoice']['to'])); ;?> </td>
<td align='center'><?php echo $Invoices['Invoice']['subject']; ?></td>
<td align='center'><?php echo $Invoices['Invoice']['datecreated']; ?></td>
<td align='center'><a href="viewinvoice"><button>View Invoice</button></a><a href="disputeinvoice"><button>Dispute Invoice</button></a></td>
</tr>
<?php endforeach; ?>
</table>在代码中,我对它进行了硬编码,这样用户15就可以查看他的所有发票,但我不想让我的系统硬编码。我希望将其设置为$id='currentuser',但不确定如何编码。
用户登录功能
public function login() {
$this->set('title_for_layout', 'Individual Registration');
$this->set('stylesheet_used', 'style');
$this->set('image_used', 'eBOXLogo.jpg');
if ($this->request->is('post')){
$this->request->data['User']['password'] = 'qazwsx';
if ($this->Auth->login()) {
$this->redirect($this->Auth->redirect('eboxs/home'));
$this->Session->write('Myid',$myid);
}
else {
$this->Session->setFlash('Username or password is incorrect');
}
}else{
$this->Session->setFlash('Welcome, please login');
}
}任何帮助都将不胜感激
发布于 2012-05-24 13:02:36
对于当前用户,您需要拥有会话,假设会话包含user_id。尝尝这个
public function payInvoice(){
$id=$this->Session->read('user_id');
$this->set('title_for_layout', 'Pay Invoice');
$this->set('stylesheet_used', 'homestyle');
$this->set('image_used', 'eBOXLogoHome.jpg');
$this->layout='home_layout';
$this->set('Invoices', $this->Invoice->findByBiller($id));
}发布于 2012-05-24 12:10:44
为什么不分配一个带有值的会话id作为user_id呢?
发布于 2012-05-24 13:11:11
当用户成功登录时,U将其id设置在会话中,
$this->Session->write('Myid',$myid);当用户名和密码正确时,从数据库获取$myid
并在控制器中的任意位置获取,例如,
$id = $this->Session->read('Myid');而且不需要添加到app_controller文件中
https://stackoverflow.com/questions/10730996
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