ExpandoObject便利工厂？

Question

ExpandoObject有什么方便的工厂方法吗？就像，我不知道，

dynamic disney = new ExpandoObject("First", "Donald", "Last", "Duck");

Answer 1

不，没有，但你可以在几分钟内写出来。:)在这里：

C#

class Program
{
    static void Main(string[] args)
    {
        dynamic ex = ExpandoFactory.Create("First", "Donald", "Last", "Duck");
        Console.WriteLine(ex.First);
        Console.WriteLine(ex.Last);
    }
}

static class ExpandoFactory
{
    internal static ExpandoObject Create(params string[] items)
    {
        //safety checks omitted for brevity
        IDictionary<string, object> result = new ExpandoObject();
        for (int i = 0; i < items.Length; i+=2)
        {
            result[items[i]] = items[i + 1];
        }
        return result as ExpandoObject;
    }
}

当然，你应该事先检查数组的基数。我希望这能帮到你。