我想搜索列表并在列表中再次显示结果,所以我使用了addtextchangelistener,但找不到使用subtext的listview的方法
下面是我的代码:
package com.android;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.LineNumberReader;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.StringTokenizer;
import android.app.ListActivity;
import android.os.Bundle;
import android.text.Editable;
import android.text.TextWatcher;
import android.util.Log;
import android.view.View;
import android.widget.ArrayAdapter;
import android.widget.EditText;
import android.widget.ListView;
import android.widget.SimpleAdapter;
import android.widget.TextView;
public class MyListDemoActivity extends ListActivity {
/** Called when the activity is first created. */
TextView tv;
//** List<String> content;
EditText actv;
List<String> arr_sort;
//** ArrayAdapter<String> adapter;
SimpleAdapter simpleadapter;
ListView lv;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
String line = " ";
LineNumberReader linenoreader = null;
StringTokenizer stringtokanixer = null;
//** content = new ArrayList<String>();
List<Map<String,String>> data= new ArrayList<Map<String,String>>();
lv = (ListView) findViewById(android.R.id.list);
try {
InputStream istream = getResources().openRawResource(R.raw.grelist);
InputStreamReader streamreader = new InputStreamReader(istream);
linenoreader = new LineNumberReader(streamreader);
linenoreader.mark(15);
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}// try catch ends here
Log.v("getting", "working");
for(int i=0;i<8;i++)
{
Map<String,String> datum= new HashMap<String,String>(2);
try {
line = linenoreader.readLine();
Log.v("item",line);
} catch (IOException e) {
e.printStackTrace();
}
Log.v("getting", line);
stringtokanixer = new StringTokenizer(line);
String st = stringtokanixer.nextToken();
String meaning="";
while (stringtokanixer.hasMoreTokens()) {
meaning +=" " +stringtokanixer.nextToken();
}// for ends
// map is used to add word and meaning
datum.put("word",st);
datum.put("meaning",meaning);
data.add(datum);
//List<String> is usedto add
//** content.add(st);
}
simpleadapter = new SimpleAdapter(this, data, android.R.layout.simple_list_item_2, new String[]{"word","meaning"}, new int[]{android.R.id.text1,android.R.id.text2});
// setListAdapter(adapter);
lv.setAdapter(simpleadapter);
tv = (TextView) findViewById(R.id.textView1);
actv = (EditText) findViewById(R.id.editText1);
/*
actv.addTextChangedListener(new TextWatcher() {
int len = 0;
@Override
public void onTextChanged(CharSequence s, int start, int before,
int count) {
arr_sort = new ArrayList<String>();
len = actv.getText().length();
for (int i = 0; i < content.size(); i++) {
if (len <= content.get(i).length()) {
if (actv.getText()
.toString()
.trim()
.equalsIgnoreCase(
(String) content.get(i).subSequence(0,
len))) {
arr_sort.add(content.get(i));
Log.v("infor loop afterTextChanged", s.toString());
}
}
}
// adapter.notifyDataSetChanged();
adapter = new ArrayAdapter<String>(MyListDemoActivity.this,
android.R.layout.simple_list_item_1, arr_sort);
setListAdapter(adapter);
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count,
int after) {
Log.v("beforetextchange","hello here");
}
@Override
public void afterTextChanged(Editable s) {
Log.v("aftertextchange","hello here");
}
}); // text watcher class ends here
*/
}// on create ends here
public void onListItemClick(ListView ls, View v, int position, long id) {
//tv.setText(content.get(position));
// tv.setText(content[position]) // in case of string
}// endsd here onListItemClick(
}发布于 2012-05-18 02:32:58
下面是我如何更改您的代码以使其正常工作:
1.我会删除arr_sort变量,并添加另一个ArrayList Maps来保存过滤后的值:
// List<String> arr_sort;
final ArrayList<Map<String, String>> data =
new ArrayList<Map<String, String>>();
final ArrayList<Map<String, String>> filteredData =
new ArrayList<Map<String, String>>();我也会让它们成为最终的,因为当我们可以修改它们的内容时,给它们分配全新的值是没有意义的。
2. simpleadapter应始终显示过滤后的数据,因此需要进行修改:
filteredData.addAll(data); // fill up filteredData initially with the whole list
simpleadapter = new SimpleAdapter(this, filteredData,
android.R.layout.simple_list_item_2,
new String[] { "word", "meaning" },
new int[] {android.R.id.text1, android.R.id.text2 });3.接下来,我将过滤代码从onTextChanged方法移到afterTextChanged方法,以根据输入的整个文本执行过滤。使用Regexp也比所有字符串操作(+,substring...)消耗的资源更少。
这样,您的TextWatcher实现将如下所示:
actv.addTextChangedListener(new TextWatcher()
{
@Override
public void onTextChanged(CharSequence s, int start, int before, int count)
{}
@Override
public void beforeTextChanged(CharSequence s,int start,int count,int after)
{}
@Override
public void afterTextChanged(Editable s)
{
Log.v("MLDA", "afterTextChanged");
// a temporary source list for better performance:
// if it's possible, use the smaller filtered list
final ArrayList<Map<String, String>> tmpSource =
new ArrayList<Map<String,String>>();
tmpSource.addAll(
(filterText.length() > 0 && s.toString().contains(filterText))
? filteredData : data);
filterText = s.toString();
// a temporary result list to fill with the filtered data
final ArrayList<Map<String, String>> tmpResult =
new ArrayList<Map<String,String>>();
if (filterText.length() == 0)
tmpResult.addAll(data); //if no filter, return the base data
else
{
final Pattern pattern =
Pattern.compile("(?i)" + Pattern.quote(s.toString()));
Matcher matcher;
for (final Map<String, String> map : tmpSource)
{
//first match against the "word":
matcher = pattern.matcher(map.get("word"));
if (!matcher.find())
{
//if no matches were found, try to match the "meaning"
matcher = pattern.matcher(map.get("meaning"));
if (!matcher.find())
continue; //if no match, move to the next map
}
tmpResult.add(map); //match found: add to new list
}
}
filteredData.clear();
filteredData.addAll(tmpResult);
simpleadapter.notifyDataSetChanged(); // update display
}
});使用临时列表可以在不更新gui的情况下构建整个过滤数据(如果直接向filteredData列表删除/添加项目,适配器将触发更新方法)。
还要注意,通过检查新的过滤器文本是否包含旧的文本,我们可以使用当前的filteredData列表作为源。
类似地,如果filterText是一个空字符串,那么就没有必要执行任何匹配,我们可以简单地返回base列表。
发布于 2012-05-22 13:46:23
发布于 2012-05-18 20:00:40
我所理解的是:-你只是想过滤ListView。对吗?
如果我误解了问题,请告诉我!
main.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical"
android:layout_width="fill_parent" android:layout_height="fill_parent">
<EditText android:id="@+id/search" android:layout_width="fill_parent" android:layout_height="wrap_content"
android:inputType="text" />
<ListView android:id="@+id/list" android:layout_width="fill_parent" android:layout_height="fill_parent" />
</LinearLayout>ListViewSearchActivity
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import android.app.Activity;
import android.os.Bundle;
import android.text.Editable;
import android.text.TextWatcher;
import android.widget.EditText;
import android.widget.ListView;
import android.widget.SimpleAdapter;
public class ListViewSearchActivity extends Activity implements TextWatcher {
private SimpleAdapter simpleAdapter;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
EditText search = (EditText) findViewById(R.id.search);
search.addTextChangedListener(this);
List<Map<String, String>> data = new ArrayList<Map<String, String>>();
for(int i=0;i<8;i++) {
Map<String,String> map = new HashMap<String, String>(2);
map.put("word", "word " + i);
map.put("meaning", "meaning " + (i + 10));
data.add(map);
}
ListView listView = (ListView) findViewById(R.id.list);
this.simpleAdapter = new SimpleAdapter(this, data, android.R.layout.simple_list_item_2, new String[]{"word","meaning"}, new int[]{android.R.id.text1,android.R.id.text2});
listView.setAdapter(this.simpleAdapter);
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {
}
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
}
@Override
public void afterTextChanged(Editable s) {
this.simpleAdapter.getFilter().filter(s.toString());
}
}https://stackoverflow.com/questions/10579922
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