设置变量的PHP语法

Question

我有一个JS脚本，我正在将代码转换成PHP，但我卡在正确的语法是什么，在我的PHP脚本中创建与JS中的这段代码相同：

var sdata = {
           "13":{
               "22":["618","22","1","1","0","0","0"],
               "21":["617","22","1","1","0","0","0"]
           },               
           "14":{
                "22":["619","22","1","1","0","0","0"],
                "20":["622","22","1","1","0","0","0"]
           },    
           "15":{
                "20":["623","22","1","1","0","0","0"]
     }
};

有什么想法吗？

Answer 1

$sdata = array(
           "13" => array(
               "22" => array("618","22","1","1","0","0","0"),
               "21" => array("617","22","1","1","0","0","0")
           ),               
           "14" => array(
                "22" => array("619","22","1","1","0","0","0"),
                "20" => array("622","22","1","1","0","0","0")
           ),    
           "15" => array(
                "20" => array("623","22","1","1","0","0","0")
     )
);

Answer 2

最简单的方法是使用jQuery .get函数，将此数组作为数据的一部分发送过来，然后对$_GET变量运行PHP函数json_decode以获得PHP数组:)如果需要硬编码数组，则可以print_r该数组。

Answer 3

查看多维数组：

http://php.net/manual/en/language.types.array.php