如何从文本中提取内容？

Question

我有一个脚本提供了一些ip地址的信息。

我想从文本中提取国家。

在下面的文本中，国家/地区行是"Country: US"

我只想显示：US

正文是：

[Querying whois.arin.net]
[whois.arin.net]
#
# Query terms are ambiguous.  The query is assumed to be:
#     "n 173.194.74.100"
#
# Use "?" to get help.
#

#
# The following results may also be obtained via:
# http://whois.arin.net/rest/nets;q=173.194.74.100?showDetails=true&showARIN=false&ext=netref2
#

NetRange:       173.194.0.0 - 173.194.255.255
CIDR:           173.194.0.0/16
OriginAS:       AS15169
NetName:        GOOGLE
NetHandle:      NET-173-194-0-0-1
Parent:         NET-173-0-0-0-0
NetType:        Direct Allocation
RegDate:        2009-08-17
Updated:        2012-02-24
Ref:            http://whois.arin.net/rest/net/NET-173-194-0-0-1


OrgName:        Google Inc.
OrgId:          GOGL
Address:        1600 Amphitheatre Parkway
City:           Mountain View
StateProv:      CA
PostalCode:     94043
Country:        US
RegDate:        2000-03-30
Updated:        2011-09-24
Ref:            http://whois.arin.net/rest/org/GOGL

OrgTechHandle: ZG39-ARIN
OrgTechName:   Google Inc
OrgTechPhone:  +1-650-253-0000 
OrgTechEmail:  arin-contact@google.com
OrgTechRef:    http://whois.arin.net/rest/poc/ZG39-ARIN

OrgAbuseHandle: ZG39-ARIN
OrgAbuseName:   Google Inc
OrgAbusePhone:  +1-650-253-0000 
OrgAbuseEmail:  arin-contact@google.com
OrgAbuseRef:    http://whois.arin.net/rest/poc/ZG39-ARIN

#
# ARIN WHOIS data and services are subject to the Terms of Use
# available at: https://www.arin.net/whois_tou.html
#

Answer 1

如果它只是您需要的正则表达式-试试这个-国家id将在第一个组中

Country:\s*([A-Z]{2})

• Country: -匹配literals
• \s* -匹配任意数量的空格，制表符etc.
• ([A-Z]{2}) -匹配并捕获任意字母(大写)两次

如果需要此模式的所有匹配项，请使用preg_match_all

Answer 2

使用preg_match，您可以执行以下操作：

if (preg_match('/^Country:\s*([A-Z]{2,3)$/m', $str, $match)) {
    echo $match[1];
}

Answer 3

有一个用于处理whois数据的phpwhois库。它将得到一个数组形式的响应。