未定义对另一个类文件中方法的引用，如何修复？

Question

我一直在做一个程序，它将做一些关于音频，SPL等的方程。

我决定让主类文件为用户提供一个选项来选择他想要做的方程式，而方程式则保存在另一个类文件中。

主类文件只是为了测试maxPeakSPL()而设置的，但是我不能让它运行。

main.cpp

//Kh[a]os
#include "equations.h"
#include <iostream>

void mainLoop();

int maxSPL = 0;

int main()
{
std::cout << "Created by Kh[a]os" << std::endl << std::endl;
mainLoop();

return 0;
}

void mainLoop()
{

std::cout << "hi";
maxSPL = equations::maxPeakSPL();
std::cout << std::endl << maxSPL << "db" << std::endl << std::endl;


    }

equations.h

#ifndef EQUATIONS_H
#define EQUATIONS_H

#include <string>


class equations
{
    public:
        equations();
        static int maxPeakSPL();
    protected:
    private:
};

#endif // EQUATIONS_H

equations.cpp

#include "equations.h"
#include <iostream>
#include <string>

equations::equations()
{

}

static int maxPeakSPL()
{

    int Sens = 0;
    double Distance = 0;
    int Watts = 0;
    int sWatts = 2;
    int eWatts = 0;
    double maxSPL = 0;
    double counter = 0;
    double wall = 0;
    std::string corner = "";

bool v = true;

    std::cout << "Sensitivity (db): " << std::endl;
    std::cin >> Sens;
    std::cout << "Amplification (watts): " << std::endl;
    std::cin >> Watts;
    std::cout << "Listening Distance (meters): " << std::endl;
    std::cin >> Distance;
    std::cout << "Distance from Wall (ft): " << std::endl;
    std::cin >> wall;
    std::cout << "Are you they in a corner? (y/n): " << std::endl;
    std::cin >> corner;


    maxSPL = Sens - (Distance*3 - 3);


while(v == true)
{
if (sWatts > Watts)
        {
            v = false;
            eWatts = sWatts;
            sWatts = sWatts/2;
            Watts = Watts-sWatts;
            counter = (double)Watts/(double)eWatts;
            counter = counter*3;
            maxSPL = maxSPL + counter;

        }

     if (v == true)
     {
        maxSPL = maxSPL + 3;
        sWatts = sWatts*2;
     }

    }
    if (wall <= 4)
    maxSPL = maxSPL + 3;

    if (corner == "Y" || corner == "YES" || corner == "y" || corner == "yes")
    maxSPL = maxSPL + 3;

    return maxSPL;

}

当我运行它时，我得到的错误是:未定义对‘error：：maxPeakSPL()’的引用。

我不知道如何解决这个问题，任何帮助都会很好。谢谢。

Answer 1

在main中，尝试将函数放在main块之前。在指令/标志的名称前加上下划线。