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SQL:组合update和group-by?
EN

Stack Overflow用户
提问于 2012-04-17 16:35:01
回答 2查看 181关注 0票数 0

我有两张表:

events

代码语言:javascript
复制
mac | na
----------
abc | (null)
abc | (null)
def | (null)

enrichments

代码语言:javascript
复制
mac | na  | timestamp
---------------------
abc | na1 | 1
abc | na2 | 2
abc | na3 | 3
def | na4 | 1

现在我想用enrichments.na中的值更新events.na列,其中mac匹配,timestamp是该特定mac的最大timestamp

对于此示例,结果将为:

代码语言:javascript
复制
abc | na3
abc | na3
def | na4

做这件事最有效的方法是什么?

谢谢!

EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2012-04-17 17:16:52

代码语言:javascript
复制
UPDATE events AS e
SET na = 
    ( SELECT n.na
      FROM enrichments AS n
      WHERE n.mac = e.mac
      ORDER BY n.timestamp DESC
      FETCH FIRST 1 ROWS ONLY
    ) 
票数 1
EN

Stack Overflow用户

发布于 2012-04-17 16:45:02

这应该适用于使用通用表表达式的SQL Server

代码语言:javascript
复制
create table events (mac nvarchar(3), na nvarchar(3))
insert into events values ('abc',null);
insert into events values ('abc',null);
insert into events values ('def',null);

create table enrichments (mac nvarchar(3), na nvarchar(3), timestamp int)
insert into enrichments values ('abc','na1',1)
insert into enrichments values ('abc','na2',2)
insert into enrichments values ('abc','na3',3)
insert into enrichments values ('def','na4',1)

with latestEnrichment (mac, latestTimestamp) as
    (select mac, MAX(timestamp)
    from    enrichments
    group by mac)
update  events
set     na = en.na
from    events e join enrichments en on e.mac = en.mac
        join latestEnrichment le on en.timestamp = le.latesttimestamp and
        en.mac = le.mac
票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/10187799

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