我有一个从erlang进程接收数据的c++代码。我得到了一个元组,并使用ei_ decode _ tuple _header/4,我获得了列表的数量,然后使用for循环遍历元组的元素,并像这样解码每个元素:
void decode_tuple(char *buff) {
int index = 0;
int size;
int type;
int res = ei_decode_tuple_header(buff, &index, &size);
if(res == 0) {
cout<<"Success"<<endl;
} else {
cout<<"Fail"<<endl;
}
for(int i = 0; i < size; ++i) {
char *p = (char*)malloc(sizeof(char) * 1000);
int res = ei_decode_string(buff, &index, p);
if(res == 0) {
cout<<"Success"<<endl;
} else {
cout<<"Fail"<<endl;
}
cout<<"The decoded string is "<<p<<endl;
}
}然而,只有当tuple/list中的所有元素都属于同一类型时,这种方法才能正常工作。不管是什么术语,我都想解码。我知道有ei_decode_term,但是文档太糟糕了,我不知道该怎么做?
谁来帮帮忙!谢谢@
发布于 2016-04-21 12:41:53
你有没有尝试过使用ei_decode_ei_term,比如:
void decode_tuple(char *buff) {
int index = 0;
int size;
int type;
int res = ei_decode_tuple_header(buff, &index, &size);
if(res == 0) {
cout << "Success" << endl;
} else {
cout << "Fail" << endl;
}
for(int i = 0; i < size; ++i) {
ei_term term;
int res = ei_decode_ei_term(buff, &index, &term);
if (res == 0) {
cout << "Success" << endl;
} else {
cout << "Fail" << endl;
}
cout << "The decoded data is " << term.value << endl;
}
}ei_term的定义如下:
typedef struct {
char ei_type;
int arity;
int size;
union {
long i_val;
double d_val;
char atom_name[MAXATOMLEN_UTF8];
erlang_pid pid;
erlang_port port;
erlang_ref ref;
} value;
} ei_term;因此,您可能需要检查term.ei_type以获得更好的解析
https://stackoverflow.com/questions/36757254
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