首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >访问外部生成的数组中的值

访问外部生成的数组中的值
EN

Stack Overflow用户
提问于 2016-04-21 02:46:23
回答 2查看 138关注 0票数 0

我正在获取电压读数,并将其转换为压力读数。这是我第一次真正体验C语言,所以我的代码很乱,但到目前为止一切正常。我面临的问题是让程序计算介于最小值和最大期望值之间的读数(存储在数组datai中)的数量。

这是代码,Sum2和count是给我带来麻烦的地方。Sum2正在添加999个值,而不是过滤,而计数总是导致998,而它本应接近500

编辑:

大泰的读数是电压,而我是在压力下工作。我的校准曲线是P=(V-2.9674)/.404

代码语言:javascript
复制
    //Voltage readings for NI USB-6009 built from the ground up

#include "stdafx.h"
#include "stdio.h"
#include "NIDAQmx.h"
#include "math.h"
#include "tdmwriter.h"
#include "fundtypes.h"
#include "platdefines.h"



#define DAQmxErrChk(functionCall) if( DAQmxFailed(error=(functionCall)) ) goto Error; else

int main(void)
{
    int32       error = 0;
    TaskHandle  taskHandle = 0;
    int32       read;
    float64     data[1000], Sum=0, Average, Variance, Deviation=0, std_dev, min=0, max=0, num=0, avg=0, minP=0, maxP=0, avgP=0, avgP2=0, minP2=0, maxP2=0, minV=0, maxV=0, avgV=0, Sum2 = 0;
    char        errBuff[2048] = { '\0' };
    int         i, count = 0;

    /*********************************************/
    // DAQmx Configure Code
    /*********************************************/
    DAQmxErrChk(DAQmxCreateTask("Pressure Voltage\n", &taskHandle));
    DAQmxErrChk(DAQmxCreateAIVoltageChan(taskHandle, "Dev1/ai0", "", DAQmx_Val_Cfg_Default, -10.0, 10.0, DAQmx_Val_Volts, NULL));
    DAQmxErrChk(DAQmxCfgSampClkTiming(taskHandle, "", 100.0, DAQmx_Val_Rising, DAQmx_Val_FiniteSamps, 1000));

    /*********************************************/
    // DAQmx TDMS Configure Code
    /*********************************************/
    DAQmxErrChk(DAQmxConfigureLogging(taskHandle, "C:\\TestData\\LogFile.tdms", DAQmx_Val_LogAndRead, "ECS Test Data", DAQmx_Val_OpenOrCreate));
    //DAQmxWriteAnalogF64(taskHandle,1000, 1 /*autoStart*/, -1 /*timeout*/, DAQmx_Val_GroupByScanNumber, data, 1000, NULL);

    /*********************************************/
    // DAQmx Start Code
    /*********************************************/
    DAQmxErrChk(DAQmxStartTask(taskHandle));
    printf("Voltage due to Pressure:\n");
    printf("\n");
    printf("Recording Data...\n");
    DAQmxErrChk(DAQmxWaitUntilTaskDone(taskHandle, 10.0));


    /*********************************************/
    // DAQmx Read Code
    /*********************************************/
    DAQmxErrChk(DAQmxReadAnalogF64(taskHandle, 1000, 10.0, DAQmx_Val_GroupByChannel, data, 1000, &read, NULL));

    printf("Acquired %d points\n", (int)read);


    /*********************************************/
    //Display Values
    /*********************************************/
    printf("\n");
    printf("values:\n");
    printf("Voltage 1= %f\n",data[10]);
    printf("Voltage 2= %f\n", data[100]);
    printf("Voltage 3= %f\n", data[200]);
    printf("Voltage 4= %f\n", data[300]);
    printf("Voltage 5= %f\n", data[400]);
    printf("Voltage 6= %f\n", data[500]);
    printf("Voltage 7= %f\n", data[600]);
    printf("Voltage 8= %f\n", data[700]);
    printf("Voltage 9= %f\n", data[800]);
    printf("Voltage 10= %f\n", data[900]);
    printf("\n");

    //for (int i = 1; i < 1000; i++) {
    //  printf("Voltage %i= %f\n",i, data[i]);
    //}
    //printf("\n");

    /*********************************************/
    //Average Values
    /*********************************************/
    for (i = 1; i < 999; ++i) {
        Sum = Sum + data[i];
    }

    Average = (Sum / 999);
    printf("Average= %f\n", Average);


    /*********************************************/
    //Standard Deviation
    /*********************************************/
    for (i = 1; i < 999; ++i) {
        Deviation = Deviation + pow((Average - data[i]), 2);
    }

    Variance = Deviation / 999;
    printf("Variance= %f\n", Variance);

    std_dev = sqrt(Variance);
    printf("Standard Deviation= %f\n", std_dev);

    printf("\n");


    /*********************************************/
    //Min and Max Values
    /*********************************************/

    {
        max = fmax(data[2], data[999]);
    }
    {
        min = fmin(data[2], data[999]);
    }

    printf("Min: %f\n", min);
    printf("Max: %f\n", max);
    printf("Log File located in C:\\TestData. Please rename LogFile.tdms after testing\n");
    printf("\n");


    /*********************************************/
    //Convert to Pressure Readings
    /*********************************************/
    printf("Pressure Readings (inches H2O):\n");
    {
        minP = (min - 2.9674) / .404;
        maxP = (max - 2.9674) / .404;
        avgP = (Average - 2.9674) / .404;
    }
    printf("Min Pressure: %f\n", minP);
    printf("Max Pressure: %f\n", maxP);
    printf("Average Pressure: %f\n", avgP);
    printf("\n");


    /*********************************************/
    //New Voltage and Pressure Averages
    /*********************************************/
    {//target min and max pressure
        minP2 = avgP - (avgP / 10);
        maxP2 = avgP + (avgP / 10);
    }
    {//target min and max voltage
        minV = (minP2*.404) + 2.9674;
        maxV = (maxP2*.404) + 2.9674;
    }
    {//Sum of values in desired range
        for (i = 1; i < 999; ++i) {
            if (minV < data[i] && data[i] < maxV); { Sum2 = Sum2 + data[i]; }
    }
    }
    {//Number of values in desired range
        for (i = 1; i < 999; i++)
        {
            if (minV < data[i] && data[i] < maxV);
            {
                count++;
            }
        }
    }
    {//New average voltage
        avgV = Sum2 / count;
    }
    {//New average pressure
        avgP2 = ((avgV - 2.9674) / .404);
    }
    printf("Adjusted Values:\n");
    printf("Min P2= %f\n", minP2);
    printf("Max P2= %f\n", maxP2);
    printf("Min Voltage= %f\n", minV);
    printf("Max Voltage= %f\n", maxV);
    printf("Sum Voltage= %f\n", Sum2);
    printf("Count= %d\n", count);
    printf("AvgV= %f\n", avgV);
    printf("AvgP= %f\n", avgP2);


Error:
    if (DAQmxFailed(error))
        DAQmxGetExtendedErrorInfo(errBuff, 2048);
    if (taskHandle != 0) 
    {
        /*********************************************/
        // DAQmx Stop Code
        /*********************************************/

        DAQmxStopTask(taskHandle);
        DAQmxClearTask(taskHandle);
    }

    if (DAQmxFailed(error))
        printf("DAQmx Error: %s\n", errBuff);
    printf("End of program, press Enter key to quit...\n");
    getchar();
    return 0;
}
EN

回答 2

Stack Overflow用户

发布于 2016-04-21 03:00:16

C是从零开始的索引,所以你每次都会跳过第一个值,这可能会也可能不会给出一个错误的值。额外的括号导致您无法正确设置条件。我用注释标记了不好的,这样你就可以看到它了。

代码语言:javascript
复制
sum2 = 0; // not needed since initialized above
count = 0; // not needed since initialized above
for (i = 0; i < 999; ++i) 
{
    if ((minV < data[i]) && (data[i] < maxV)) // ; messed up and forced code to execute
    // Extra parens are just for readability
    {
        //Sum of values in desired range
        Sum2 += data[i];
        //Number of values in desired range
        count++;
    }
}
票数 0
EN

Stack Overflow用户

发布于 2016-04-21 03:04:23

下面几行后面有一个错误的;

代码语言:javascript
复制
if (minV < data[i] && data[i] < maxV);

代码语言:javascript
复制
if (minV < data[i] && data[i] < maxV);

这会导致下面的代码块总是被执行,因为;创建了一个“什么都不做”的代码块。

编辑:你是不是也对minVmaxV做了错误的计算?他们和压力有什么关系?

代码语言:javascript
复制
minV = (minP2*.404) + 2.9674;
maxV = (maxP2*.404) + 2.9674;

也许这会使数据超出它们的范围,因为循环无法捕获任何值。

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/36752539

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档