我尝试将网页图片保存到本地,我在这里使用代码来判断,如果图片文件名结尾不是.jpg、.jpeg、.png或.gif,则添加它们。我使用stripos,但我遇到了一些麻烦,当一个图像的网址像这样。那么该如何解决呢?谢谢。
$webimage = 'http://pcdn.500px.net/5953805/d0dd841969187f47e8ad9157713949b4b95b3bda/4.jpg?1333782904356';
$pieces = explode("/", $webimage);
$pathend = end($pieces);
$imageinfo = @getimagesize($webimage);
$imagetype= $imageinfo['mime'];
if($imagetype=='image/jpeg'){
if(stripos($pathend,'.jpg')==0){
$newpathend = $pathend.'.jpg'; // if image end is't '.jpg', add '.jpg'
}else if(stripos($pathend,'.jpeg')==0){
$newpathend = $pathend.'.jpeg'; // if image end is't '.jpg', add '.jpeg'
}else{
$newpathend = $pathend;// if image end is '.jpg' or '.jpeg', do not change
}
}
if($imagetype=='image/png'){
if(stripos($pathend,'.png')==0){
$newpathend = $pathend.'.png'; // if image end is't '.png', add '.png'
}else{
$newpathend = $pathend;// if image end is '.png', do not change
}
}
if($imagetype=='image/gif'){
if(stripos($pathend,'.gif')==0){
$newpathend = $pathend.'.gif'; // if image end is't '.gif', add '.gif'
}else{
$newpathend = $pathend;// if image end is '.gif', do not change
}
}发布于 2012-04-07 19:31:07
你可以这样试一下
$type=Array(1 => 'jpg', 2 => 'jpeg', 3 => 'png', 4 => 'gif'); //store all the image extension types in array
$imgname = ""; //get image name here
$ext = explode(".",$imgname); //explode and find value after dot
if(!(in_array($ext[1],$type))) //check image extension not in the array $type
{
//your code here
}发布于 2012-04-08 15:04:30
为什么不使用preg_match?
if( preg_match('/\.(jpg|jpeg|png|gif)(?:[\?\#].*)?$/i', $webimage, $matches) ) {
// matching file extensions are in $matches[1]
}发布于 2012-04-07 16:07:51
此函数pathinfo可能会对您有所帮助。
https://stackoverflow.com/questions/10052845
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