条件条件为

Question

您好，如何使if语句更有效？基本上我想做的是检查扑克中的“手”是否“直”我想检查玩家是否有“直”，“同花顺”和以上。例如:如果游戏手牌是同花顺的，我不需要检查是否笔直，只需检查“同花顺”及以上即可。

public enum HandType
{
    Single = 1,
    Pair = 2,
    Triple = 3,
    Straight = 4,
    Flush = 5,
    FullHouse = 6,
    FourOfAKind = 7,
    StraightFlush = 8,
}

public List<CardData> GetBotHands(List<CardData> gameHand)
{
    List<CardData> playerHand = new List<CardData>();

    HandType handType = HandEvaluator.EvaluateHand(gameHand);

    if(handType < HandType.Straight)
    {
        return null;
    }

    if(handType == HandType.Straight)
    {
        playerHand = GetStraight(gameHand);
        if(playerHand != null)
        {
            return playerHand;
        }

        playerHand = GetFlush(gameHand);
        if (playerHand != null)
        {
            return playerHand;
        }

        playerHand = GetFullHouse(gameHand);
        if (playerHand != null)
        {
            return playerHand;
        }

        playerHand = GetFourKind(gameHand);
        if (playerHand != null)
        {
            return playerHand;
        }

        playerHand = GetStraightFlush(gameHand);
        if (playerHand != null)
        {
            return playerHand;
        }
    }
    else if(handType == HandType.Flush)
    {
        playerHand = GetFlush(gameHand);
        if (playerHand != null)
        {
            return playerHand;
        }

        playerHand = GetFullHouse(gameHand);
        if (playerHand != null)
        {
            return playerHand;
        }

        playerHand = GetFourKind(gameHand);
        if (playerHand != null)
        {
            return playerHand;
        }

        playerHand = GetStraightFlush(gameHand);
        if (playerHand != null)
        {
            return playerHand;
        }
    }
    else if(handType == HandType.FullHouse)
    ...

    return null;
}

通过遵循@Shiran Dror的解决方案，现在我有了以下代码。但是有没有办法让它变得更短呢？

if(handType == HandType.Straight)
{
    return GetStraight(gameHand) ?? GetFlush(gameHand) ?? GetFullHouse(gameHand) ?? GetFourKind(gameHand) ?? GetStraightFlush(gameHand);
}
else if(handType == HandType.Flush)
{
    return GetFlush(gameHand) ?? GetFullHouse(gameHand) ?? GetFourKind(gameHand) ?? GetStraightFlush(gameHand);
}
else if(handType == HandType.FullHouse)
...

Answer 1

你可以使用?？如下所示：

return GetStraight(gameHand) ?? GetFlush(gameHand) ... ?? GetStraightFlush(gameHand);

它将返回第一个none空值

编辑-让它更短

switch (handType) {
  case HandType.Straight:
    return GetStraight(gameHand) ?? GetFlush(gameHand) ... ?? GetStraightFlush(gameHand);

  case HandType.Flush:
    return GetStraight(gameHand) ?? GetFlush(gameHand) ... ?? GetStraightFlush(gameHand);
...
  default: 
    return null;
}

此外，如果您一次又一次地调用同一个函数，您可以添加一个新函数，这样就不会重复代码。示例：

private HandType RepetitiveCheck(gameHand) 
{
  return GetFlush(gameHand) ?? GetFullHouse(gameHand) ?? GetFourKind(gameHand) ?? GetStraightFlush(gameHand)
}

在main函数中，像这样使用它

switch (handType) {
  case HandType.Straight:
    return GetStraight(gameHand) ?? RepetitiveCheck(gameHand);

  case HandType.Flush:
    return RepetitiveCheck(gameHand);
...
  default: 
    return null;
}