Sentinel循环不会运行

Question

我的程序可以编译，但我遇到了几个问题。我的第一个要求e/E结束的cout语句可以工作，但是在我声明(+ || - || * || /)的第二个while循环中不会运行。+/-/*//返回“操作类型无效”。你们能帮我找出我的错误吗？

第一个前哨循环，只是学习循环：

#include <iostream>

using namespace std;

int main()
{
    int numOne;
    int numTwo;
    int result;
    string operation;

    cout << "Please enter what operation you'd like to perform or e/E to end program: ";
    cin >> operation;
    while (operation == "e" || "E")
    {
        cout << "Operation type invalid." << endl;
        cout << "Please enter what operation you'd like to perform or e/E to end program: ";
        cin >> operation;
    }

    while (operation == "+" || operation == "-" || operation == "*" || operation == "/")
    {
        cout << "Please enter integer one: " << endl;
        cin >> numOne;
        cout << "Please enter integer two: " << endl;
        cin >> numTwo;

    if (operation == "+")
    {
        result = numOne + numTwo;
        cout << "The numbers you entered were " << numOne << "," << numTwo << endl;
        cout << "The operation you chose was " << operation << "." << endl;
        cout << "The operations result is " << result << "." << endl;
        cout << "Your equation was: " << numOne << " " << operation << " " << numTwo << " = " << result << ".";
    }
    else if (operation == "-")
    {
        result = numOne - numTwo;
        cout << "The numbers you entered were " << numOne << "," << numTwo << endl;
        cout << "The operation you chose was " << operation << "." << endl;
        cout << "The operations result is " << result << "." << endl;
        cout << "Your equation was: " << numOne << " " << operation << " " << numTwo << " = " << result << ".";
    }
    else if (operation == "*")
    {
        result = numOne * numTwo;
        cout << "The numbers you entered were " << numOne << "," << numTwo << endl;
        cout << "The operation you chose was " << operation << "." << endl;
        cout << "The operations result is " << result << endl;
        cout << "Your equation was: " << numOne << " " << operation << " " << numTwo << " = " << result << ".";
    }
    else if (operation == "/")
    {
        if (numTwo == 0)
        {
                cout << "You cannot divide by zero!" << endl;
        }
        else
        {
        result = numOne / numTwo;
        cout << "The numbers you entered were " << numOne << "," << numTwo << endl;
        cout << "The operation you chose was " << operation << "." << endl;
        cout << "The operations result is " << result << endl;
        cout << "Your equation was: " << numOne << " " << operation << " " << numTwo << " = " << result << ".";
        }
    }

    }
    return 0;
}

Answer 1

while (operation == "e" || "E")

这里比较的是以下两种情况之一：

1. Does operation == "E" "e"
2. If not，a
   1. aoperation=="E"？

第二个条件就是你的问题："E"当然是一个有效的指针，所以这个条件总是true。一直都是。请注意，在第二种情况下，您没有将operation与"E"进行比较。

你永远被困在这里：

while (operation == "e" || "E")
{
    cout << "Operation type invalid." << endl;
    cout << "Please enter what operation you'd like to perform or e/E to end program: ";
    cin >> operation;
}

您只需具备以下条件：

while (operation == "e" || operation == "E")

这可能只是一个打字错误或疏忽。