使用导入将XSD转换为XML

Question

我目前正在开发一个生成XML文件的服务，它遵循发票的UBL标准，因此我需要使用一些提供的XSD模式。

我正在用.NET C#进行开发，并且找到了一种可以将XSD映射到C#类的方法--通过使用XSD.exe --这看起来行吗？

我面临的问题是，xsd文件中还有其他名称空间，这似乎会给我生成的类(xsd:imports)带来一些问题：

<!-- ===== xsd:schema Element With Namespaces Declarations ===== -->
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"
targetNamespace="urn:oasis:names:specification:ubl:schema:xsd:Invoice-2"
xmlns="urn:oasis:names:specification:ubl:schema:xsd:Invoice-2"
xmlns:cac="urn:oasis:names:specification:ubl:schema:xsd:CommonAggregateComponents-2"
xmlns:cbc="urn:oasis:names:specification:ubl:schema:xsd:CommonBasicComponents-2"
xmlns:udt="urn:un:unece:uncefact:data:specification:UnqualifiedDataTypesSchemaModule:2"
xmlns:ccts="urn:un:unece:uncefact:documentation:2"
xmlns:ext="urn:oasis:names:specification:ubl:schema:xsd:CommonExtensionComponents-2"
xmlns:qdt="urn:oasis:names:specification:ubl:schema:xsd:QualifiedDatatypes-2"
elementFormDefault="qualified"
attributeFormDefault="unqualified"
version="2.0">
<!-- ===== Imports ===== -->
<xsd:import namespace="urn:oasis:names:specification:ubl:schema:xsd:CommonAggregateComponents-2" schemaLocation="../common/UBL-CommonAggregateComponents-2.0.xsd"/>
<xsd:import namespace="urn:oasis:names:specification:ubl:schema:xsd:CommonBasicComponents-2" schemaLocation="../common/UBL-CommonBasicComponents-2.0.xsd"/>
<xsd:import namespace="urn:un:unece:uncefact:data:specification:UnqualifiedDataTypesSchemaModule:2" schemaLocation="../common/UnqualifiedDataTypeSchemaModule-2.0.xsd"/>
<xsd:import namespace="urn:oasis:names:specification:ubl:schema:xsd:CommonExtensionComponents-2" schemaLocation="../common/UBL-CommonExtensionComponents-2.0.xsd"/>
<xsd:import namespace="urn:oasis:names:specification:ubl:schema:xsd:QualifiedDatatypes-2" schemaLocation="../common/UBL-QualifiedDatatypes-2.0.xsd"/>
<!-- ===== Root Element ===== -->
<xsd:element name="Invoice" type="InvoiceType">
...

我使用以下命令运行xsd.exe：

xsd.exe /c C:\Users\tn\Downloads\os-UBL-2.0\os-UBL-2.0\xsd\maindoc\UBL-Invoice-2.0.xsd C:\Users\tn\Downloads\os-UBL-2.0\os-UBL-2.0\xsd\common\UBL-CommonAggregateComponents-2.0.xsd C:\Users\tn\Downloads\os-UBL-2.0\os-UBL-2.0\xsd\common\UBL-CommonBasicComponents-2.0.xsd C:\Users\tn\Downloads\os-UBL-2.0\os-UBL-2.0\xsd\common\UnqualifiedDataTypeSchemaModule-2.0.xsd C:\Users\tn\Downloads\os-UBL-2.0\os-UBL-2.0\xsd\common\UBL-CommonExtensionComponents-2.0.xsd C:\Users\tn\Downloads\os-UBL-2.0\os-UBL-2.0\xsd\common\UBL-QualifiedDatatypes-2.0.xsd C:\Users\tn\Downloads\os-UBL-2.0\os-UBL-2.0\xsd\common\CodeList_UnitCode_UNECE_7_04.xsd C:\Users\tn\Downloads\os-UBL-2.0\os-UBL-2.0\xsd\common\CodeList_MIMEMediaTypeCode_IANA_7_04.xsd C:\Users\tn\Downloads\os-UBL-2.0\os-UBL-2.0\xsd\common\CodeList_LanguageCode_ISO_7_04.xsd C:\Users\tn\Downloads\os-UBL-2.0\os-UBL-2.0\xsd\common\CodeList_CurrencyCode_ISO_7_04.xsd

当我尝试使用生成的代码生成XML文件时，输出如下所示，其中缺少imports和namespacepreceders，最终导致验证失败。

<?xml version="1.0" encoding="utf-8"?>
<Invoice xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"     xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="urn:oasis:names:specification:ubl:schema:xsd:Invoice-2">
   <UBLVersionID xmlns="urn:oasis:names:specification:ubl:schema:xsd:CommonBasicComponents-2">2.0</UBLVersionID>
   <LegalMonetaryTotal xmlns="urn:oasis:names:specification:ubl:schema:xsd:CommonAggregateComponents-2">
   <LineExtensionAmount currencyID="DKK" xmlns="urn:oasis:names:specification:ubl:schema:xsd:CommonBasicComponents-2">200</LineExtensionAmount>
   <PayableAmount currencyID="DKK" xmlns="urn:oasis:names:specification:ubl:schema:xsd:CommonBasicComponents-2">300</PayableAmount>
   </LegalMonetaryTotal>
</Invoice>

在这里，我通过一个xmlserializer从生成的类生成XML。

XmlSerializer mySerializer = new XmlSerializer(typeof(InvoiceType));
    InvoiceType invoice = new InvoiceType();

    UBLVersionIDType UVer = new UBLVersionIDType();
    UVer.Value = "2.0";
    invoice.UBLVersionID = UVer;

    MonetaryTotalType mtt = new MonetaryTotalType();
    LineExtensionAmountType lep = new LineExtensionAmountType();
    lep.currencyID = CurrencyCodeContentType.DKK;
    lep.Value = 200;
    PayableAmountType pat = new PayableAmountType();
    pat.currencyID = CurrencyCodeContentType.DKK;
    pat.Value = 300;

    mtt.LineExtensionAmount = lep;
    mtt.PayableAmount = pat;

    invoice.LegalMonetaryTotal = mtt;
    StreamWriter sw = new StreamWriter(@"C:\New folder\test2.xml");

    mySerializer.Serialize(sw, invoice);
    sw.Close();

我如何解决这个问题，这是在.NET中创建遵循xsd模式的XML的最好/最简单的方法吗？

Answer 1

我自己发现的。

需要XmlSerializerNamespaces-object，它包含XML文档的名称空间和前缀。

(http://msdn.microsoft.com/en-us/library/system.xml.serialization.xmlserializernamespaces.aspx)