我需要一个正则表达式来验证MMM dd yyyy格式的日期(包括闰年)
我发现了一个正则表达式,但目前它在每个闰年的2月29号出现错误
^(?:(((January|March|May|July|August|October|December) 31)|((January|March|April|May|June|July|August|September|October|November|December) (([0-2]\\d)|30))|(February ([01]\\d|2[0-8])))|(February 29(?=-((1[6-9]|[2-9]\\d)(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00))))) ((1[6-9]|[2-9]\\d)\\d{2})$请帮我修一下。
提前感谢
发布于 2012-03-02 19:34:20
下面是一个检查日期字符串有效性的函数,同时考虑到格式:
function chkdate(datestr,formatstr){
if (!(datestr && formatstr)) {return false;}
var splitter = formatstr.match(/\-|\/|\s/) || ['-']
,df = formatstr.split(splitter[0])
,ds = datestr.split(splitter[0])
,ymd =[0,0,0]
,dat;
for (var i=0;i<df.length;i++){
if (/yyyy/i.test(df[i])) {ymd[0] = ds[i];}
else if (/mm/i.test(df[i])) {ymd[1] = ds[i];}
else if (/dd/i.test(df[i])) {ymd[2] = ds[i];}
}
dat = new Date(ymd.join('/'));
return !isNaN(dat) && Number(ymd[1])<=12 && dat.getDate()===Number(ymd[2]);
}
//usage (in your case)
var months = {january:1,february:2,march:3,april:4,may:5,
june:6,july:7,august:8,september:9,october:10,
november:11,december:12},
inputdateraw = 'february 29 2011'.split(' '),
inputdate = [months[inputdateraw[0]],
inputdateraw[1],
inputdateraw[2]].join(' ');
console.log(chkdate (inputdate, 'mm dd yyyy')); //=> false另请参阅this SO-question
发布于 2015-04-16 22:52:09
您是否可以尝试使用下面的代码:
"^(?:(((Jan(uary)?|Ma(r(ch)?|y)|Jul(y)?|Aug(ust)?|Oct(ober)?|Dec(ember)?)\\ 31)|((Jan(uary)?|Ma(r(ch)?|y)|Apr(il)?|Ju((ly?)|(ne?))|Aug(ust)?|Oct(ober)?|Sep(tember)?|(Nov|Dec)(ember)?)\\ (0?[1-9]|([12]\\d)|30))|(Feb(ruary)?\\ (0?[1-9]|1\\d|2[0-8]|(29(?=,\\ ((1[6-9]|[2-9]\\d)(0[48]|[2468][048]|[13579][26])|((16|[2468][048]|[3579][26])00)))))))\\,\\ ((1[6-9]|[2-9]\\d)\\d{2}))"发布于 2012-03-02 19:09:33
如果你使用的是jquery,那么你可以使用它附带的date picker。
或者你可以使用验证插件。您可以使用addMethod函数对其进行自定义。
$.validator.addMethod(
"australianDate",
function(value, element) {
// put your own logic here, this is just a (crappy) example
return value.match(/^\d\d?\/\d\d?\/\d\d\d\d$/);
},
"Please enter a date in the format dd/mm/yyyy"
);然后在你的表单上:
$('#myForm')
.validate({
rules :
myDate : {
australianDate : true
}
});请参阅here
还有一个javascript日期库- Datejs
https://stackoverflow.com/questions/9532055
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