这是一张桌子
fid uid time
12 34 1
1 34 2
15 34 5
1 33 10
12 33 10
1 33 12
13 33 15
16 34 123
22 32 453
1 32 456
1 33 457
1 32 460现在我想计算每个uid的数量,其中time is >9和fid=1如下所示
uid number of duplications
33 3
32 2发布于 2012-01-23 03:27:51
SELECT uid, COUNT(*) FROM table WHERE fid=1 AND `time` > 9 GROUP BY uidhttps://stackoverflow.com/questions/8963929
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