File::Find::Rule::LibMagic:保留未定义值的选项可以吗？

Question

是否可以保留未定义值的选项(在本例中为“maxdepth”)？

#!/usr/bin/env perl
use warnings;
use 5.012;
use File::Find::Rule::LibMagic qw(find);
use Getopt::Long qw(GetOptions);

my $max_depth;
GetOptions ( 'max-depth=i' => \$max_depth );
my $dir = shift;

my @dbs = find( file => magic => 'SQLite*', maxdepth => $max_depth, in => $dir );
say for @dbs;

或者我应该这样写：

if ( defined $max_depth ) {
    @dbs = find( file => magic => 'SQLite*', maxdepth => $max_depth, in => $dir );
} else {
    @dbs = find( file => magic => 'SQLite*', in => $dir );
}

Answer 1

通过使用一个值为undef的变量将maxdepth设置为undef应该没有问题。Perl中的每个变量都以undef值开头。

更多细节

File::Find::Rule::LibMagic扩展了File::Find::Rule。File::Find::Rule中的find函数以：

sub find {
    my $object = __PACKAGE__->new();

new函数返回：

bless {
    rules    => [],
    subs     => {},
    iterator => [],
    extras   => {},
    maxdepth => undef,
    mindepth => undef,
}, $class;

请注意，默认情况下，maxdepth设置为undef。

Answer 2

好的?它可能不会混淆File::Find::Rule

$ perl -MFile::Find::Rule -le " print for File::Find::Rule->maxdepth(undef)->in( q/tope/ ) "
tope
tope/a
tope/b
tope/c
tope/c/0
tope/c/1
tope/c/2

$ perl -MFile::Find::Rule -le " print for File::Find::Rule->maxdepth(1)->in( q/tope/ ) "
tope
tope/a
tope/b
tope/c

$ perl -MFile::Find::Rule -le " print for File::Find::Rule->maxdepth(-1)->in( q/tope/ ) "
tope

$ perl -MFile::Find::Rule -le " print for File::Find::Rule->maxdepth(2)->in( q/tope/ ) "
tope
tope/a
tope/b
tope/c
tope/c/0
tope/c/1
tope/c/2

$ pmvers File::Find::Rule
0.33