如何使用ASK-SDK v2中的handlerInput获取自定义意图槽值

Question

我正在使用ASK-SDK v2创建一个基本的计算器技能。我不确定如何在新版本中将用户提供的槽值放入Lambda代码中。我能够让它与旧版本一起工作。

对话用户:打开calculate Alexa:你可以要求我进行加、减、乘、除用户:将2加3 Alexa: 2加3的和是5

下面是我的IntentSchema

{
    "interactionModel": {
        "languageModel": {
            "invocationName": "calculate",
            "intents": [
                {
                    "name": "AMAZON.CancelIntent",
                    "samples": []
                },
                {
                    "name": "AMAZON.HelpIntent",
                    "samples": []
                },
                {
                    "name": "AMAZON.StopIntent",
                    "samples": []
                },
                {
                    "name": "AddIntent",
                    "slots": [
                        {
                            "name": "numA",
                            "type": "AMAZON.NUMBER"
                        },
                        {
                            "name": "numB",
                            "type": "AMAZON.NUMBER"
                        }
                    ],
                    "samples": [
                        "Sum of {numA} and {numB}",
                        "add {numA} and {numB}"
                    ]
                },
                {
                    "name": "SubIntent",
                    "slots": [
                        {
                            "name": "numA",
                            "type": "AMAZON.NUMBER"
                        },
                        {
                            "name": "numB",
                            "type": "AMAZON.NUMBER"
                        }
                    ],
                    "samples": [
                        "difference between {numA} and {numB}",
                        "subtract {numA} from {numB}"
                    ]
                },
                {
                    "name": "ProductIntent",
                    "slots": [
                        {
                            "name": "numA",
                            "type": "AMAZON.NUMBER"
                        },
                        {
                            "name": "numB",
                            "type": "AMAZON.NUMBER"
                        }
                    ],
                    "samples": [
                        "multiply {numA} and {numB}",
                        "product of {numA} and {numB}"
                    ]
                },
                {
                    "name": "DivideIntent",
                    "slots": [
                        {
                            "name": "numA",
                            "type": "AMAZON.NUMBER"
                        },
                        {
                            "name": "numB",
                            "type": "AMAZON.NUMBER"
                        }
                    ],
                    "samples": [
                        "divide {numB} by {numA}",
                        "divide {numA} by {numB}"
                    ]
                },
                {
                    "name": "ExponentialIntent",
                    "slots": [
                        {
                            "name": "numA",
                            "type": "AMAZON.NUMBER"
                        },
                        {
                            "name": "numB",
                            "type": "AMAZON.NUMBER"
                        },
                        {
                            "name": "numC",
                            "type": "AMAZON.NUMBER"
                        }
                    ],
                    "samples": [
                        "{numA} raised to the power of {numB} by {numC}",
                        "{numA} raised to the power {numB}"
                    ]
                },
                {
                    "name": "AMAZON.NavigateHomeIntent",
                    "samples": []
                }
            ],
            "types": []
        }
    }
}

我在这里添加了addintenthandler。请告诉我，我从意图中获取槽值的方法是否正确，或者我是否应该使用sessionattribute

const AddIntentHandler = {
    canHandle(handlerInput) {
        return handlerInput.requestEnvelope.request.type === 'IntentRequest'
            && handlerInput.requestEnvelope.request.intent.name === 'AddIntent';
    },
    handle(handlerInput) {
        var output1 = "";
        var num1 = handlerInput.resuestEnvelope.request.intent.slots.numA.value;
        var num2 = handlerInput.resuestEnvelope.request.intent.slots.numB.value;
        if((num1)&&(num2)){
            output1 = 'The sum of ' +num1+ ' and ' +num2+ ' is ' + (num1+num2);
        }
        else {
            output1 = 'Enter valid number';
        }
        const speechText = output1;
        return handlerInput.responseBuilder
            .speak(speechText)
            .reprompt(speechText)
            .getResponse();
    }
};

Alexa回复"Unable to process skill response“欢迎任何帮助

Answer 1

更新: SDK中现在有了内置函数: Alexa.getSlotValue(handlerInput.requestEnvelope，“someSlotName”的Alexa.getSlotValue() (返回字符串值)和getSlot() (返回Slot对象)

老答案:你有一个拼写错误，resuestEnvelope应该是requestEnvelope。在任何情况下，我都创建了完全相同的技能，一个计算器(在西班牙语中，但它基本上是相同的东西)，并且我使用了一个称为getSlotValues()的辅助函数，我鼓励您重用它。当您必须捕获自定义插槽(处理方式不同，因为实体解析结构不同)时，它也会很好地工作：

https://github.com/germanviscuso/skill-sample-nodejs-mycalculator