如何使用asp-classic处理XML/XPath并将字符串解析为xml文档

Question

用asp从字符串请求参数中读取XML Xpath的最好方法是什么？

  <%    function FReadXml(pStringXml) 
  {
      var xDom = new ActiveXObject("MSXML2.DOMDocument");
      var a = xDom.LoadXML(pStringXml)
      return a;
   }
var xml = Request.QueryString("xml").item;
try{
  var dom = FReadXml(xml);
  //work with xpath
 }catch(ex0){
  Response.Write("problems when read a xml: " + ex0.message);
 }

%>

谢谢，非常感谢。

Answer 1

我不知道你想说什么解析字符串到xml文档，但我可以帮助你使用Xpath的一部分

您可以通过SelectSingleNode({XPath Expression})使用XPath加载单个节点

var xmlDoc = Server.CreateObject("Msxml2.DOMDocument.6.0");
var currNode;
xmlDoc.async = false;
xmlDoc.load("books.xml");
if (xmlDoc.parseError.errorCode != 0) {
   var myErr = xmlDoc.parseError;
   Response.write("You have error " + myErr.reason);
} else {
   xmlDoc.setProperty("SelectionLanguage", "XPath");
   currNode = xmlDoc.selectSingleNode("//book/author");
   Response.write(currNode.text);
}

或者使用SelectNodes({XPath Expression})

var xmlDoc = Server.CreateObject("Msxml2.DOMDocument.3.0");
var objNodeList;
xmlDoc.async = false;
xmlDoc.load("hello.xsl");
if (xmlDoc.parseError.errorCode != 0) {
   var myErr = xmlDoc.parseError;
   Response.write("You have error " + myErr.reason);
} else {
   xmlDoc.setProperty("SelectionNamespaces",    "xmlns:xsl='http://www.w3.org/1999/XSL/Transform'");
   xmlDoc.setProperty("SelectionLanguage", "XPath");
   objNodeList = xmlDoc.documentElement.selectNodes("//xsl:template");
   Response.write(objNodeList.length);
}

你也可以看到这个帖子：

StackOverflow - How can I get the XML nodes from this XML in classic ASP (MSXML)?

关于如何将字符串解析成MSXML文档有一种方法，就像您在评论中指出的那样，这是一种创建您自己的xml字符串并进行操作的简单方法

示例：

var xmlDoc = Server.CreateObject("Msxml2.DOMDocument.3.0");
xmlDoc.async = false;
xmlDoc.loadXML("<customer><first_name>Joe</first_name><last_name>Smith</last_name></customer>");
if (xmlDoc.parseError.errorCode != 0) {
   var myErr = xmlDoc.parseError;
   Response.Write("You have error " + myErr.reason);
} else {
   Response.Write(xmlDoc.xml);
}