TypeError：“NoneType”对象在使用google API的python代码中没有“”__getitem__“”属性

Question

我有这段代码，它使用google API在google中搜索一个单词，但这一次它工作得很好，但如果我添加了很多单词，或者如果我多次运行它，我总是得到以下错误...

    results = jsonResponse['responseData']['results']
TypeError: 'NoneType' object has no attribute '__getitem__'

我试着在谷歌上搜索了很多次，但不知道问题出在哪里。谁可以帮助我了解这个问题和如何处理它…正在与这个错误作斗争

 import urllib
    import urllib2
    from urllib import urlencode
    import json as m_json
    from urllib2 import urlopen
    import re
    import json
    from nltk.corpus import stopwords
    import sys
    from urllib2 import urlopen
    import urllib2
    import simplejson
    import pprint

    words = ['headache','diabetes','myopia','dhaed','snow','blindness','head','ache','acne','aids','blindness','head','ache','acne','aids','blindness','head','ache','acne','aids']


    for word in words:
     url = ('https://ajax.googleapis.com/ajax/services/search/web'
           '?v=1.0&q='+word+'&userip=192.168.1.105')
     request = urllib2.Request(url)
     response = urllib2.urlopen(request)
     jsonResponse=json.loads(response.read())
     #print "the response now is: ",jsonResponse
     #pprint.pprint(jsonResponse)
     results = jsonResponse['responseData']['results']
     for result in results:
      print "\nthe result is: ",result
      url =result['url']
      print "\nthe url is: ",url
      try:
       page=urllib2.urlopen(url).read()
      except urllib2.HTTPError,err:
       if err.code == 403:
        print "bad"
        continue
       else:
        print "good"
        break
      except urllib2.HTTPError:
        print "server error"
      except:
       print "dont know the error"

感谢就是进步..

Answer 1

当没有结果时，jsonResponse['responseData']可能是None，因此在结果中没有名为results的属性，或者responseData本身是None (== JSON null)。(字典查找失败，因为jsonResponse或jsonResponse['responseData']为null/None。

当该错误发生时，转储输出以查看哪个是None，然后在results = jsonResponse['responseData']['results']行之前添加对它的检查。

Answer 2

Aneroid对响应数据的判断是正确的。

处理此问题的一个可能的解决方案是：

responseData = jsonResponse['responseData']
if responseData is not None:
    results = responseData['results']
    for results in results:
        # your code
else:
    print "No Response"