Table1
Code, desc, type id
01 Rajan 1
01 Sajan 1
01 Vijayan 2
01 Suresh 3
01 Caresh 4
01 Sujesh 4
01 vikran 4
02 desk 1
02 card 2
02 villa 2
02 megash 2
02 supan 3
....我想按类型id查看该表。
预期输出
Code type-1 type-2 type-3 type-4
01 Rajan Vijayan suresh caresh
01 Sajan null null Sujan
01 null null null vikran
02 desk card supan null
02 null villa null null
02 null megash null null如何查询上述条件
需要查询帮助
发布于 2011-12-25 17:12:49
因此,首先,只需升级您的数据。请注意,我将添加一个标识行id,以便稍后使用。
IF OBJECT_ID('tempdb..#test') IS NOT NULL
drop table #test
IF OBJECT_ID('tempdb..#Numbered') IS NOT NULL
drop table #Numbered
CREATE TABLE #test (Code CHAR(2), [DESC] varchar(10), [type id] INT, RowNumber INT IDENTITY(1,1))
INSERT #test
VALUES ('01', 'Rajan', 1),
('01' ,'Sajan', 1),
('01' ,'Vijayan', 2),
('01' ,'Suresh', 3),
('01' ,'Caresh', 4),
('01' ,'Sujesh', 4),
('01' ,'vikran', 4),
('02' ,'desk', 1),
('02' ,'card' ,2),
('02' ,'villa', 2),
('02', 'megash', 2),
('02', 'supan', 3)然后,我们创建一个保存区域,它使用行id来计算每个名称应该继续显示在代码的哪一行。
CREATE TABLE #Numbered
(
RowNum int, Code CHAR(2), [type] VARCHAR(10), [DESC] VARCHAR(10)
)
INSERT #Numbered
SELECT (select count(*) from #test where code=t1.Code AND [type id]=t1.[type id] AND RowNumber<=t1.RowNumber),
code,
[type id],
[DESC]
FROM #test t1最后,我们在数据上创建一个数据透视表(以“伪造”该操作符的标准SQL2000方式完成)。然后,我们将“数据透视表”放在一个派生select中,该select只返回我们想要的列,但允许我们对code和rownum列进行排序,以生成您要求的输出。
SELECT Code,[type-1],[type-2],[type-3],[type-4]
FROM (Select P.Code,RowNum
, Min( Case When type = '1' Then [DESC] End ) As [type-1]
, Min( Case When type = '2' Then [DESC] End ) As [type-2]
, Min( Case When type = '3' Then [DESC] End ) As [type-3]
, Min( Case When type = '4' Then [DESC] End ) As [type-4]
From #Numbered As P
Group By P.Code,RowNum) R
ORDER BY Code,RowNum如果你需要进一步的解释,请让我知道。
发布于 2011-12-25 17:03:18
Select t1.code, t1.description, t2.description, t3.description from
(Select code, description from table where type=1) t1,
(Select code, description from table where type=2) t2,
(Select code, description from table where type=3) t3,
(Select code, description from table where type=4) t4
Where t1.code=t2.code and t2.code=t3.code and t3.code=t4.code and t4.code=t1.code
and t4.code=t2.code and t1.code=t3.code尝试此查询,它不会返回null,但会返回重复的值
如果您有任何疑问,请联系
https://stackoverflow.com/questions/8628573
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