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使用HTML5和servlet的视频
EN

Stack Overflow用户
提问于 2011-12-21 22:47:56
回答 4查看 17.7K关注 0票数 6

下面给出的代码用于视频流。这在IE9和火狐上很好,但在Chrome和Mac Safari上就不好了。

代码语言:javascript
复制
import java.io.*;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

/**
 * Servlet implementation class VideoStreamServlet
 */

public class VideoStreamServlet extends HttpServlet {
    private static final long serialVersionUID = 1L;

    /**
     * Default constructor. 
     */
    public VideoStreamServlet() {
        // TODO Auto-generated constructor stub
    }

    /**
     * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        // TODO Auto-generated method stub
        String range = request.getHeader("range");
        String browser = request.getHeader("User-Agent");
        System.out.println(browser);
        if(browser.indexOf("Firefox") != -1){
            System.out.println("==========ITS FIREFOX=============");
            byte[] data = getBytesFromFile(new File("D:/media/final.ogg"));
            response.setContentType("video/ogg");
            response.setContentLength(data.length);
            response.setHeader("Content-Range", range + Integer.valueOf(data.length-1));
            response.setHeader("Accept-Ranges", "bytes");
            response.setHeader("Etag", "W/\"9767057-1323779115364\"");
            byte[] content = new byte[1024];
            BufferedInputStream is = new BufferedInputStream(new ByteArrayInputStream(data));
            OutputStream os = response.getOutputStream();
            while (is.read(content) != -1) {
                //System.out.println("... write bytes");
                os.write(content);
            }
            is.close();
            os.close();
        }

        else if(browser.indexOf("Chrome") != -1){
            System.out.println("==========ITS Chrome=============");
            byte[] data = getBytesFromFile(new File("D:/media/final.mp4"));
            String diskfilename = "final.mp4";
            response.setContentType("video/mp4");
            //response.setContentType("application/octet-stream");
            response.setHeader("Content-Disposition", "attachment; filename=\"" + diskfilename + "\"" );
            System.out.println("data.length " + data.length);
            response.setContentLength(data.length);
            response.setHeader("Content-Range", range + Integer.valueOf(data.length-1));
            response.setHeader("Accept-Ranges", "bytes");
            response.setHeader("Etag", "W/\"9767057-1323779115364\"");
            byte[] content = new byte[1024];
            BufferedInputStream is = new BufferedInputStream(new ByteArrayInputStream(data));
            OutputStream os = response.getOutputStream();
            while (is.read(content) != -1) {
                //System.out.println("... write bytes");
                os.write(content);
            }
            is.close();
            os.close();
        }

        else if(browser.indexOf("MSIE") != -1) {
            System.out.println("==========ITS IE9=============");
            byte[] data = getBytesFromFile(new File("D:/media/final.mp4"));
            String diskfilename = "final.mp4";
            response.setContentType("video/mpeg");
            //response.setContentType("application/octet-stream");
            response.setHeader("Content-Disposition", "attachment; filename=\"" + diskfilename + "\"" );
            System.out.println("data.length " + data.length);
            response.setContentLength(data.length);
            response.setHeader("Content-Range", range + Integer.valueOf(data.length-1));
            response.setHeader("Accept-Ranges", "text/x-dvi");
            response.setHeader("Etag", "W/\"9767057-1323779115364\"");
            byte[] content = new byte[1024];
            BufferedInputStream is = new BufferedInputStream(new ByteArrayInputStream(data));
            OutputStream os = response.getOutputStream();
            while (is.read(content) != -1) {
                //System.out.println("... write bytes");
                os.write(content);
            }
            is.close();
            os.close();
        }
        else if( browser.indexOf("CoreMedia") != -1) {
            System.out.println("============ Safari=============");
            byte[] data = getBytesFromFile(new File("D:/media/final.mp4"));
            String diskfilename = "final.mp4";
            response.setContentType("video/mpeg");
            //response.setContentType("application/octet-stream");
            response.setHeader("Content-Disposition", "attachment; filename=\"" + diskfilename + "\"" );
            System.out.println("data.length " + data.length);
            //response.setContentLength(data.length);
            //response.setHeader("Content-Range", range + Integer.valueOf(data.length-1));
           // response.setHeader("Accept-Ranges", " text/*, text/html, text/html;level=1, */* ");
           // response.setHeader("Etag", "W/\"9767057-1323779115364\"");
            byte[] content = new byte[1024];
            BufferedInputStream is = new BufferedInputStream(new ByteArrayInputStream(data));
            OutputStream os = response.getOutputStream();
            while (is.read(content) != -1) {
                //System.out.println("... write bytes");
                os.write(content);
            }
            is.close();
            os.close();
        }
    }

    /**
     * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        // TODO Auto-generated method stub
    }   
     private static byte[] getBytesFromFile(File file) throws IOException {
        InputStream is = new FileInputStream(file);
        //System.out.println("\nDEBUG: FileInputStream is " + file);
        // Get the size of the file
        long length = file.length();
        //System.out.println("DEBUG: Length of " + file + " is " + length + "\n");
        /*
         * You cannot create an array using a long type. It needs to be an int
         * type. Before converting to an int type, check to ensure that file is
         * not loarger than Integer.MAX_VALUE;
         */
        if (length > Integer.MAX_VALUE) {
            System.out.println("File is too large to process");
            return null;
        }
        // Create the byte array to hold the data
        byte[] bytes = new byte[(int)length];
        // Read in the bytes
        int offset = 0;
        int numRead = 0;
        while ( (offset < bytes.length)
                &&
                ( (numRead=is.read(bytes, offset, bytes.length-offset)) >= 0) ) {
            offset += numRead;
        }
        // Ensure all the bytes have been read in
        if (offset < bytes.length) {
            throw new IOException("Could not completely read file " + file.getName());
        }
        is.close();
        return bytes;
    }

}
EN

回答 4

Stack Overflow用户

回答已采纳

发布于 2011-12-21 23:01:38

老实说,这种方法是绝对不正确的。

  • 您正在嗅探服务器端的用户代理,并依赖于其上的业务作业。在任何情况下,这都不是一个好主意。如果您只想根据用户代理指定一个不同的文件,那么在HTML端,借助JavaScript或CSS就可以做到这一点。这两种客户端语言都能够识别真正的浏览器,而无需嗅探用户代理字符串(即spoofable).
  • You不能正确响应Range请求。您将发送回完整的文件,而不是请求的Range。Firefox和IE不使用range请求,这就是它“有效”的原因。Chrome和Safari使用range请求。

这应该可以在不嗅探用户代理和正确响应Range请求的情况下由RandomAccessFile而不是Filebyte[]实现。考虑到所有的HTTP specification需求只需要相当多的代码,所以这里只提供了一个链接,您可以在其中找到这样一个servlet的具体示例:FileServlet supporting resume and caching

但是,更好的方法是将作业委托给servletcontainer的默认servlet。例如,如果是Tomcat,那么您需要做的就是将以下行添加到/conf/server.xml

代码语言:javascript
复制
<Context docBase="D:\media" path="/media" />

这样,所需的媒体文件就可以通过http://localhost:8080/media/final.ogghttp://localhost:8080/media/final.mp4获得,而不需要自行开发servlet。

票数 11
EN

Stack Overflow用户

发布于 2011-12-22 00:38:40

这似乎更多的是一个格式支持问题。

你可以试试ogg格式。HTML5代码是

代码语言:javascript
复制
<audio controls="controls">
  <source src="song.ogg" type="audio/ogg" />
  Your browser does not support the audio tag.
</audio>
票数 1
EN

Stack Overflow用户

发布于 2011-12-21 23:00:51

Google Chrome不支持H.264 (包括mp4),所以你也需要在google chrome上使用final.ogg。而对于safari,您需要更改此行

代码语言:javascript
复制
browser.indexOf("CoreMedia") != -1

添加"Safari“而不是"CoreMedia”

我希望它能起作用。

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/8591666

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