使用ajax在MVC中导出

Question

我正在尝试通过ajax导出在我的控制器中创建的zip文件。我看了几个相关的问题，但它们都略有不同，我无法将它们联系起来。有时，我什么也得不到。其他时候，我的ajax转到窗口位置，所有东西都崩溃了。

我的ajax调用：

$.ajax({
     url: "/Somewhere/Export",
     type: "POST",
     dataType: 'html',
     data: {
         jsonModel: JSON.stringify(modelData),
         fileType: $("#toggle-2").val()
      },
      success: function (returnValue) {
           window.location = '/Somewhere/Export/Download?file=' + returnValue;
      },
});

一次尝试我的控制器剪辑。：

[HttpPost, Authorize]
public ActionResult Export(string jsonModel, int? fileType)
{
    MemoryStream workingStream = GenerateExportFile(jsonModel, fileType);
    return File(workingStream, "application/zip", folderName + ".zip");
}

我也尝试过使用响应流：

[HttpPost, Authorize]
public ActionResult Export(string jsonModel, int? fileType)
{
    MemoryStream workingStream = GenerateExportFile(jsonModel, fileType);
    Response.Clear();
    Response.AddHeader("Content-Disposition", "attachment; filename=" + folderName + ".zip");
    Response.ContentType = System.Net.Mime.MediaTypeNames.Application.Zip;
    workingStream.WriteTo(Response.OutputStream);
    Response.End();
    return RedirectToAction("Index");
}

我看过的内容：Generating excel then downloading、Download excel via ajax mvc和Downloading zip through asp mvc

Answer 1

在javascript中(使用blockui和jquery-file-download插件)：

        $(window).block();
        $.fileDownload('Export', {
            httpMethod: 'POST',
            data: inputs,
            successCallback: function (url) {
                $(window).unblock();
            },
            failCallback: function (responseHtml, url) {
                $(window).unblock();
                $(window).html(url + '</br>' + responseHtml);
            }
        });

在控制器中(发送文件和设置cookie)：

    public ActionResult Export()
    {
        var e = new ExportZip();
        var request = Request.Unvalidated;
        byte[] data = e.Create(request.Form);

        Response.SetCookie(new HttpCookie("fileDownload", "true") { Path = "/" });
        return File(data, "application/zip", "file.zip");
    }