querytimes = "SELECT video_id, COUNT(src_ip) FROM video GROUP BY video_id ORDER BY COUNT(src_ip) DESC"
cur.execute (querytimes)
dltimes = cur.fetchall()
for row in dltimes:
videoid = str(row [0])
downloadtimes = int(str(row [1]))
x.append(rank)
rank = rank + 1
y.append(downloadtimes)
v.append(videoid)
counter = dict(zip(v, y))
for n in xrange(1, max(counter.itervalues()) + 1):
perc = 100. / sum(1 for nb in counter.itervalues() if nb == n) / len(counter)
if perc:
print '%.f%% videos have been downloaded %d times' % (perc, n)这是我的代码。首先,我从数据库中读取数据,然后将videoid和下载时间放入字典中,并做了一些计算,但我得到了以下错误:
perc = 100. / sum(1 for nb in counter.itervalues() if nb == n) / len(counter) ZeroDivisionError: float division
有谁能帮上忙吗?
发布于 2011-12-06 19:06:17
您是否检查过counter字典中至少有一个值与nb == n条件匹配?在我看来,结果就是你的sum或者你的len返回0…
看看这个:
>>> n = 3
>>> counter = {'a': 1}
>>> 100. / sum(1 for nb in counter.itervalues() if nb == n) / len(counter)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ZeroDivisionError: float division by zero
>>> counter = {'a': 3}
>>> 100. / sum(1 for nb in counter.itervalues() if nb == n) / len(counter)
100.0发布于 2011-12-06 19:07:26
检查counter是否为空-换句话说,dltimes中返回的值是否没有元素。我会在for循环中这样做:
if counter:
perc = 100. / sum(1 for nb in counter.itervalues() if nb == n) / len(counter)
else:
perc = 0或者,也有可能在nb == n为True的地方没有值。在这种情况下:
s = sum(1 for nb in counter.itervalues() if nb == n)
if counter and s:
perc = 100. / s / len(counter)
else:
perc = 0https://stackoverflow.com/questions/8398828
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