我目前正在编写一个组件来与基于以太网的设备通信,并且必须使用异步套接字。有时,当我从设备接收到特定的“命令”时,我需要为正在使用我的组件的任何程序(通常是WinForm)引发一个事件。我正在为用户创建一个示例表单,但我在允许客户端表单接收事件和修改表单时遇到了困难;我得到了典型的“跨线程操作无效:控件'listStrings‘从创建它的线程以外的线程访问”。
我尝试过阅读Implementing the Event-based Asynchronous Pattern和Walkthrough: Implementing a Component That Supports the Event-based Asynchronous Pattern,尽管它似乎并不是我所需要的,特别是在阅读第一个链接中的“实现基于事件的异步模式的机会”时。
.Net / C#更多的是一种爱好而不是专业,在这个项目中-这是我在能够完成它之前需要弄清楚的最后一部分。使用“线程安全”(我知道,每个人都认为它只意味着一件事)现有的TCP/IP组件是不是比自己尝试实现它更好?
编辑:这是我的网络类代码,向您展示我现在如何实现它。我忘了我是在哪里发现这个代码片段的,但在我添加表单之前,它一直工作得很好。
internal class Network
{
private Device dev;
private TcpClient client;
private NetworkStream ns;
private byte[] buffer = new byte[2048];
private Queue<byte[]> _msgQ = new Queue<byte[]>();
public Network(Device d)
{
dev = d;
}
internal void Connect(string ipAddress, int port)
{
client = new TcpClient();
client.BeginConnect(ipAddress, port, new AsyncCallback(OnConnect), null);
}
internal byte[] getLocalIp()
{
return ((IPEndPoint)client.Client.LocalEndPoint).Address.GetAddressBytes();
}
private void OnConnect(IAsyncResult ar)
{
try
{
client.EndConnect(ar);
ns = new NetworkStream(client.Client);
ns.BeginRead(buffer, 0, 2048, new AsyncCallback(OnRead), null);
while (_msgQ.Count > 0)
{
byte[] message = _msgQ.Dequeue();
ns.Write(message, 0, message.Length);
}
dev.dvDevice._connected = true;
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
}
}
internal void Disconnect()
{
try
{
client.Close();
dev.dvDevice._connected = false;
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
}
}
internal void Write(byte[] message)
{
if ((!client.Connected) || ns == null)
{
_msgQ.Enqueue(message);
return;
}
ns.Write(message, 0, message.Length);
}
private void OnWrite(IAsyncResult ar)
{
try
{
ns.EndWrite(ar);
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
}
}
private void OnRead(IAsyncResult ar)
{
try
{
int recv = ns.EndRead(ar);
byte[] message = new byte[recv];
Buffer.BlockCopy(buffer, 0, message, 0, recv);
dev.dvDevice._mh.Parse(message);
ns.BeginRead(buffer, 0, 2048, new AsyncCallback(OnRead), null);
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
}
}
}Device是向客户端公开的类。它包含一个执行所有解析的MessageHandler (_mh)类。Device包含由MessageHandler在特定响应时调用的公共事件。希望这对我到目前为止所拥有的东西有所帮助;我不希望重写太多,但为了让它正确(并正常工作),如果必要的话,我会这样做的。
EDIT (2):我对这个库的目标是,用户根本不需要管理任何线程-所以当一个事件被引发时,比如说"ReceiveString",用户应该能够不假思索地对它采取行动。
编辑(3):更多代码以确保完整性。
public delegate void OnStringEvent(byte[] str);
public class Device
{
internal struct _device
{
// other stuff too, but here's what's important
public bool _connected;
public bool _online;
public MessageHandler _mh;
public Network _net;
}
public event OnStringEvent OnString;
internal void ReceiveString(byte[] str)
{
OnString(str);
}
internal _device dvDevice;
public Device(int device_number, int system_number)
{
dvDevice = new _device(device_number, system_number);
dvDevice._mh = new MessageHandler(this);
dvDevice._net = new Network(this);
}
}
internal class MessageHandler
{
private Device dev;
public MessageHandler(Device d)
{
dev = d;
}
public void Parse(byte[] message)
{
// The code goes through the message and does what it needs to
// and determines what to do next - sometimes write back or something else
// Eventually if it receives a specific command, it will do this:
dev.ReceiveString(ParseMessage(ref _reader));
}
}发布于 2011-11-28 12:10:09
我喜欢@Polity的答案,作为一个Rx的粉丝,我会说使用Rx (反应式扩展)
//we convert a typical begin/end (IAsyncPattern) into an observable sequence
//it returns a Func -read() that takes a byte, two ints and returns one.
var read = Observable.FromAsyncPattern<byte[], int, int, int>
(networkStream.BeginRead, networkStream.EndRead)
.ObserveOn(Scheduler.Dispatcher);
// Now, you can get an IObservable instead of an IAsyncResult when calling it.
byte[] someBytes = new byte[10];
IObservable<int> observable = read(someBytes, 0, 10);
observable.Subscribe(x=>
//x will be the returned int. You can touch UI from here.
);根据您的代码,我可以看到另一个线程调用OnString事件,然后我假设当您订阅它时,您只是将字符串添加到列表框中。
device.OnString += new OnStringEvent(device_onstring);
void device_onstring(byte[] str)
{
listStrings.Items.Add(...);//this is wrong, will give cross thread op error.
//you do this:
this.Invoke(new MethodInvoker(delegate()
{
listStrings.Items.Add(..);
//or anything else that touches UI
});
// this should refer to a form or control.
}发布于 2011-11-28 11:57:28
帮你自己一个忙,依靠TPL为你做同步提升。示例:
NetworkStream stream = MySocket.NetworkStream;
// creat a Task<int> returning the number of bytes read based on the Async patterned Begin- and EndRead methods of the Stream
Task<int> task = Task<int>.Factory.FromAsync(
fs.BeginRead, fs.EndRead, data, 0, data.Length, null);
// Add the continuation, which returns a Task<string>.
return task.ContinueWith((task) =>
{
if (task.IsFaulted)
{
ExceptionTextBox.Text = task.Exception.Message;
}
else
{
ResultTextBox.Text = string.Format("Read {0} bytes into data", task.Result);
}
}, TaskScheduler.FromCurrentSynchronizationContext());发布于 2011-11-28 11:59:10
根据您的设计,您可以在两个地方处理此问题。如果该事件是从其他线程引发的,则可以通过检查处理该事件的窗体(或其他控件)的.invokeReqeuired属性,在事件处理程序中处理该事件。如果返回true,则应使用.beginInvoke方法将调用封送到适当的线程。
根据您的设计,您可以从另一端处理它,方法是向组件传递要封送到的窗体的实例。在引发事件之前,请检查.invokeRequired并封送处理调用,以便在正确的线程中引发事件。这样,使用库的代码就不必担心线程,但需要库有一个对system.windows.forms的引用。
https://stackoverflow.com/questions/8291235
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