android Json解析

Question

有人能帮我吗?我在尝试解析此API时似乎无法修复错误：

{
    "createDate": 1321834118923, 
    "result": "SUCCESS", 
    "searchTerm": "N7", 
    "searchableLocations": [
        {
            "identifier": "OUTCODE^1685", 
            "name": "N7"
        }
    ] 
}

请帮我找出问题

   package com.somcollection;

  import android.app.Activity;
  import android.os.Bundle;

  import org.json.JSONArray;
  import org.json.JSONObject;
  import android.app.Activity;
  import android.os.Bundle;

  public class JsonParser extends Activity {
private JSONObject jObject;


private String jString = "{\"searchTerm\":\"N7\",\"searchableLocations
    \":[{\"identifier\":\"OUTCODE^1685\",\"name\":\"N7\"}],\"createDate
     \":1321834118923,\"result\":\"SUCCESS\"}";

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    try {
        parse();
    } catch (Exception e) {
        e.printStackTrace();
    }
}
private void parse() throws Exception {
    jObject = new JSONObject(jString);

    JSONObject jObject = new JSONObject(jString);    
    String menuObject = jObject.getString("searchTerm");     
    JSONArray menuitemArray = jObject.getJSONArray("searchableLocations");   

    for (int i = 0; i < menuitemArray.length(); i++) {
        JSONObject jsonObj = menuitemArray.getJSONObject(i);     
        String attributeId = jsonObj.getString("identifier");     
        System.out.println(attributeId);     

        String attributeValue = jsonObj.getString("name");    
        System.out.println(attributeValue); 
    }

    String createDate = jObject.getString("jObject");
    String result = jObject.getString("result");

}
 }

Answer 1

下面的代码行将失败：

String createDate = jObject.getString("jObject");

因为在名为"jObject“JSON中没有键。我希望你能写下

String createDate = jObject.getString("createDate");

顺便说一下，您可能也不想对这个值使用getString()，因为从技术上讲，它在JSON中定义为一个整数。