mysql查询问题，如何显示值

Question

我面临着一个问题。我有一个代码：

<?php

$mysqli = new mysqli('localhost', 'test', 'test123', 'testdb');


$sql = "
        SELECT g.id as groupId, g.name as groupName, d.device_id
        FROM librenms.devices as d
        INNER JOIN librenms.device_groups as g
                ON d.hostname LIKE  CONCAT('%', mysql.SPLIT_STR(g.pattern, '\"', 2), '%')
        WHERE g.pattern LIKE '_devices.hostname%'
        ORDER BY g.id
";


$qid = $mysqli->query($qry);

if($qid->num_rows == 0){
        die("no results from MySQL\n");
}else{
        while($row = $qid->fetch_object()){     // each row
                var_dump($row);
        }
}

主要是这段代码在数据库中查找与devicegroups有相同“字符串”的设备。这没问题。但是我如何使用属于哪个组的设备分别打印所有组呢？或者我如何使用在“”之间有相同字符串的设备打印一组。？有没有人能给我一些建议或建议？

Answer 1

$qid = $mysqli->query($qry);应为$qid = $mysqli->query($sql);