我有一个链接(例如):
http://10.100.0.178:8134/hds-live/livepkgr/_definst_/liveevent.f4m如何从该链接获取server_name (http://10.100.0.178:8134/ )?有什么标准函数吗?
发布于 2011-11-22 15:54:37
发布于 2011-11-22 16:06:12
import urlparse
a = 'http://10.100.0.178:8134/hds-live/livepkgr/_definst_/liveevent.f4m'
output = '{0.scheme}://{0.netloc}'.format(urlparse.urlsplit(a))
# output == 'http://10.100.0.178:8134'发布于 2011-11-22 15:57:38
import socket
from urlparse import urlparse
ip = urlparse('http://173.194.64.104').hostname
socket.gethostbyaddr(ip)https://stackoverflow.com/questions/8223551
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