当我在JDesktopPane中有一个JInternalFrame时,JInternalFrame是可移动的(这很好)。但是,可以将它移到JDesktopPane的可见范围之外(我不太喜欢这样)
为了自己看一下,下面是一些示例代码:
public static void main(String[] args) {
JFrame frame = new JFrame("JDesktopPane");
JDesktopPane tableDisplay = new JDesktopPane();
JInternalFrame internalFrame = new JInternalFrame("JInternalFrame",true,true,true,true);
internalFrame.setContentPane(new JLabel("Content"));
internalFrame.pack();
internalFrame.setVisible(true);
tableDisplay.add(internalFrame, JDesktopPane.POPUP_LAYER);
frame.setContentPane(tableDisplay);
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setMinimumSize(new Dimension(400, 300));
frame.setVisible(true);
}是否可以设置JInternalFrame或JDesktopPane,使它们不允许这样做?
发布于 2011-11-15 23:42:56
负责移动/调整大小的协作者是DesktopPaneManager。因此,我会尝试将移动限制在窗格内。这是一个快速而粗糙的概念证明:
JDesktopPane background = new JDesktopPane();
JInternalFrame internalFrame = new JInternalFrame("Internal Frame",
true, true, true, true);
DesktopManager manager = new DefaultDesktopManager() {
/** This moves the <code>JComponent</code> and repaints the damaged areas. */
@Override
public void setBoundsForFrame(JComponent f, int newX, int newY, int newWidth, int newHeight) {
boolean didResize = (f.getWidth() != newWidth || f.getHeight() != newHeight);
if (!inBounds((JInternalFrame) f, newX, newY, newWidth, newHeight)) return;
f.setBounds(newX, newY, newWidth, newHeight);
if(didResize) {
f.validate();
}
}
protected boolean inBounds(JInternalFrame f, int newX, int newY, int newWidth, int newHeight) {
if (newX < 0 || newY < 0) return false;
if (newX + newWidth > f.getDesktopPane().getWidth()) return false;
if (newY + newHeight > f.getDesktopPane().getHeight()) return false;
return true;
}
};
background.setDesktopManager(manager);显然,有一些问题需要解决:-) F.i.
编辑
只是为了澄清一下:“无响应”是指用户必须松开并再次按下/拖动(一旦内部框架达到桌面边界)来进一步移动。这并不奇怪,因为BorderListener (由BasicInternalFrame安装的mouseListener )保留了与初始按下相关的一些状态,然后请求相对于该初始位置进行重新定位。将鼠标拖到框架所在的位置会混淆这种内部状态。
有趣的是,看一下代码,似乎有限制移动的意图,不把它推到外面,
// Make sure we stay in-bounds
if(newX + i.left <= -__x)
newX = -__x - i.left + 1;
if(newY + i.top <= -__y)
newY = -__y - i.top + 1;
if(newX + __x + i.right >= pWidth)
newX = pWidth - __x - i.right - 1;
if(newY + __y + i.bottom >= pHeight)
newY = pHeight - __y - i.bottom - 1;不过,这是相对于当前鼠标位置的。
发布于 2011-11-16 20:11:46
完全归功于克利奥帕特拉为我指明了正确的方向。
我想我已经解决了无响应的问题,并在这里分享我的解决方案。根据kleopatra的回答,如果鼠标指针位于窗格外部,则内部框架位于窗格的边缘。此外,这将继续跟随鼠标-即,如果您移动鼠标离开窗格的底部,然后转到窗格的右侧,框架将沿着窗格的底部,然后向上移动到窗格的右侧沙子。
public class BoundedDesktopManager extends DefaultDesktopManager {
@Override
public void beginDraggingFrame(JComponent f) {
// Don't do anything. Needed to prevent the DefaultDesktopManager setting the dragMode
}
@Override
public void beginResizingFrame(JComponent f, int direction) {
// Don't do anything. Needed to prevent the DefaultDesktopManager setting the dragMode
}
@Override
public void setBoundsForFrame(JComponent f, int newX, int newY, int newWidth, int newHeight) {
boolean didResize = (f.getWidth() != newWidth || f.getHeight() != newHeight);
if (!inBounds((JInternalFrame) f, newX, newY, newWidth, newHeight)) {
Container parent = f.getParent();
Dimension parentSize = parent.getSize();
int boundedX = (int) Math.min(Math.max(0, newX), parentSize.getWidth() - newWidth);
int boundedY = (int) Math.min(Math.max(0, newY), parentSize.getHeight() - newHeight);
f.setBounds(boundedX, boundedY, newWidth, newHeight);
} else {
f.setBounds(newX, newY, newWidth, newHeight);
}
if(didResize) {
f.validate();
}
}
protected boolean inBounds(JInternalFrame f, int newX, int newY, int newWidth, int newHeight) {
if (newX < 0 || newY < 0) return false;
if (newX + newWidth > f.getDesktopPane().getWidth()) return false;
if (newY + newHeight > f.getDesktopPane().getHeight()) return false;
return true;
}
}发布于 2011-11-15 21:29:45
尝试设置JFrame的FlowLayout,并使用add()方法添加JDesktopPane。
frame.setLayout(new FlowLayout());
tableDisplay.setPreferredSize(new Dimension(100,100));
frame.add(tableDisplay);https://stackoverflow.com/questions/8136944
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