Monty Hall Python模拟计算

Question

我正在尝试模拟Monty Hall问题，在这个问题中，有人选择了一扇门，然后随机移走了一扇门--最终肯定是一扇有车的门和一扇没有车的门，其中一扇肯定是有人选择的。虽然我现在不需要模拟/询问使用程序的人他们想要哪扇门，但我在实际设置计算时遇到了问题。当我运行代码时，它输出0，其中is应该大约为66%

import random

doors=[0,1,2]
wins=0

car=random.randint(0,2)
player=random.randint(0,2)

#This chooses the random door removed
if player==car:
    doors.remove.random.randint(0,2)
else:
    doors.remove(car)
    doors.remove(player)

for plays in range(100):
    if car == player:
        wins=wins+1

print(wins) 

Answer 1

你需要把你的代码放在循环中，才能让它每次都运行。你还需要确保你只允许第二次有效的选择(他们不能选择移除的门)，并且你只移除有效的门(你不能移除带有汽车的门或玩家选择的门)。

import random

wins = 0

for plays in range(100):
    doors = [0,1,2]
    car = random.choice(doors)
    player = random.choice(doors)

    # This chooses the random door removed
    doors.remove(random.choice([d for d in doors if d != car and d != player]))

    # Player chooses again (stay or switch)
    player = random.choice(doors)
    if player == car:
        wins += 1

print(wins)

但是对于Monty Hall问题，您甚至不需要跟踪门。

win_if_stay = 0
win_if_switch = 0
for i in range(100):
    player = random.randint(0, 2)
    car = random.randint(0, 2)
    if player == car:
        win_if_stay += 1
    else:
        win_if_switch += 1