如何将xml文档中节点追加到已有xml文档中

Question

我的a.xml中有锦标赛列表：

<tournaments>

    <tournament>
        <name>a</name>
    </tournament>

    <tournament>
        <name>b</name>
    </tournament>

    <tournament>
        <name>c</name>
    </tournament>

</tournaments>

广告然后我在b.xml有一个锦标赛

<tournament>
    <name>d</name>
</tournament>

如何将document b.xml作为另一个锦标赛添加到a.xml中？

这就是我想要的：

<tournaments>

    <tournament>
        <name>a</name>
    </tournament>

    <tournament>
        <name>b</name>
    </tournament>

    <tournament>
        <name>c</name>
    </tournament>

    <tournament>
        <name>d</name>
    </tournament>

</tournaments>

Answer 1

从first Document;

• Adopt

• (请参见Node )获取要从first Document；

• Adopt添加到second Document;

• Appent的Node Node (请参见Document.adopt(Node))作为第二个Document结构的子项采用的Node (请参见Node.appendChild(Node).

更新。代码：

DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = documentBuilderFactory.newDocumentBuilder();

Document tournament = builder.parse(new File("b.xml"));
Document tournaments = builder.parse(new File("a.xml"));

Node tournamentElement = tournament.getFirstChild();
Node ndetournament = tournaments.getDocumentElement();
Node firstDocImportedNode = tournaments.adoptNode(tournamentElement);
ndetournament.appendChild(firstDocImportedNode);

TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer();
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
transformer.transform(new DOMSource(tournaments), new StreamResult(System.out));

结果：

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<tournaments>
    <tournament>
        <name>a</name>
    </tournament>

    <tournament>
        <name>b</name>
    </tournament>

    <tournament>
        <name>c</name>
    </tournament>
<tournament>
    <name>d</name>
</tournament>
</tournaments>

Answer 2

这对你有用吗？

import java.io.StringBufferInputStream;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;

import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;

public class Tournament {

  private static final String tournamentData =
    "  <tournaments>" +
    "    <tournament>" +
    "        <name>a</name>" +
    "    </tournament>" +
    "    <tournament>" +
    "        <name>b</name>" +
    "    </tournament>" +
    "    <tournament>" +
    "        <name>c</name>" +
    "    </tournament>" +
    "</tournaments>";


  private static final String tournamentB =
    "    <tournament>" +
    "        <name>d</name>" +
    "    </tournament>";

  private static DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();

  public static void main(String[] args) {
    try {
      Document currentTournaments = getCurrentTournaments();
      Element tournament =  getNewTournament();
      Element ndetournament = (Element) currentTournaments.getElementsByTagName("tournaments").item(0);
      Node firstDocImportedNode = currentTournaments.importNode(tournament, true);
      ndetournament.appendChild(firstDocImportedNode);
    } catch (Exception e) {
      e.printStackTrace();
    }
  }

  private static Document getCurrentTournaments() throws Exception{
    DocumentBuilder builder = dbFactory.newDocumentBuilder();
    Document docTournament = builder.parse(new StringBufferInputStream(tournamentData));
    return docTournament;
  }

  private static Element getNewTournament() throws Exception{
    DocumentBuilder builder = dbFactory.newDocumentBuilder();
    Document newTournament = builder.parse(new StringBufferInputStream(tournamentData));
    Element tournament = newTournament.getDocumentElement();
    return tournament;
  }
}

您可以修改getXXXX()函数以适合您自己的代码