AlchemyAPI Python SDK出错

Question

我正在尝试使用AlchemyAPI Python0.7SDK。然而，当我在其中运行一个方法时，例如URLGetText(url)；

我得到了这个错误：

    nodes = etree.fromstring(result).xpath(xpathQuery)
  File "lxml.etree.pyx", line 2743, in lxml.etree.fromstring (src/lxml/lxml.etree.c:52665)
  File "parser.pxi", line 1573, in lxml.etree._parseMemoryDocument (src/lxml/lxml.etree.c:79932)
  File "parser.pxi", line 1452, in lxml.etree._parseDoc (src/lxml/lxml.etree.c:78774)
  File "parser.pxi", line 960, in lxml.etree._BaseParser._parseDoc (src/lxml/lxml.etree.c:75389)
  File "parser.pxi", line 564, in lxml.etree._ParserContext._handleParseResultDoc (src/lxml/lxml.etree.c:71739)
  File "parser.pxi", line 645, in lxml.etree._handleParseResult (src/lxml/lxml.etree.c:72614)
  File "parser.pxi", line 585, in lxml.etree._raiseParseError (src/lxml/lxml.etree.c:71955)
lxml.etree.XMLSyntaxError: AttValue: " or ' expected, line 19, column 11

这来自以下代码区域：

  def GetRequest(self, apiCall, apiPrefix, paramObject):
    endpoint = 'http://' + self._hostPrefix + '.alchemyapi.com/calls/' + apiPrefix + '/' + apiCall
    endpoint += '?apikey=' + self._apiKey + paramObject.getParameterString()
    handle = urllib.urlopen(endpoint)
    result = handle.read()
    handle.close()
    xpathQuery = '/results/status'
    nodes = etree.fromstring(result).xpath(xpathQuery)
    if nodes[0].text != "OK":
      raise Exception, 'Error making API call.'
    return result

有谁知道哪里出了问题吗？

谢谢

丹尼尔·克肖

Answer 1

我查看了Python urllib文档，发现了这个页面：

http://docs.python.org/library/urllib.html#high-level-interface

其中包含有关urllib.urlopen()返回的filehandle对象的以下警告

需要注意的是:如果size参数被省略或为负值，read()方法可能直到数据流结束时才会读取；一般情况下，没有好的方法来确定套接字中的整个流是否已被读取。

我认为在使用Python解析文件之前，您可能应该确保以etree.fromstring()字符串的形式获取文件的全部内容。类似于：

result = ''
while (1):
    next = handle.read()
    if not next: 
        break
    result += next