由于Perl是一种非常好用的语言,所以有很多这样的语句,但是任何语言中最常用的语句都是if语句和设置值的组合。我想我已经找到了其中的许多,但仍然有一些空白。最终,我们的目标是不需要多次编写变量名:
这是我到目前为止所知道的:
$r ||= $s; # $r = $s unless ($r);
$r //= $s; # $r = $s unless (defined $r);
$r &&= $s; # $r = $s if ($r);
$r = $c ? $s : $t; # if ($c) { $r = $s } else { $r = $t }
$c ? $r : $s = $t; # if ($c) { $r = $t } else { $s = $t }
$r = $s || $t; # if ($s) { $r = $s } else { $r = $t }
$r = $s && $t; # if ($s) { $r = $t } else { $r = $s = undef, 0, untrue, etc. }
$c and return $r; # return $r if ($c);
$c or return $r; # return $r unless ($c);
$c and $r = $s; # $r = $s if ($c);
@$r{qw(a b c d)} # ($r->{a}, $r->{b}, $r->{c}, $r->{d})有人在“秘密操作员”上也有一个really interesting article,如下所示:
my @part = (
'http://example.net/app',
( 'admin' ) x!! $is_admin_link,
( $subsite ) x!! defined $subsite,
$mode,
( $id ) x!! defined $id,
( $submode ) x!! defined $submode,
);然而,我发现列表中缺少的是:
$r <= $s; # read as "$r = min($r, $s);" except with short-circuiting
$r = $s if (defined $s); # what's the opposite of //?
$r and return $r # can that be done without repeating $r?还有什么值得一提的吗?还有哪些条件集变量可以用来减少代码?还遗漏了什么?
发布于 2011-10-18 03:42:24
你的问题中的这些结构可以使用low keywords and和or关键字更清楚地写出来:
$c and return $r; # return $r if ($c);
$c or return $r; # return $r unless ($c);
$c and $r = $s; # $r = $s if ($c);and和or的优点在于,与语句修饰符控制字不同,and和or可以链接到复合表达式中。
语法糖的另一个有用工具是使用for/foreach循环作为单个值的主题化。请考虑以下几点:
$var = $new_value if defined $new_value;vs
defined and $var = $_ for $new_value;或者像这样的东西:
$foo = "[$foo]";
$bar = "[$bar]";
$_ = "[$_]" for $foo, $bar;map函数也可以以这种方式使用,它有一个可以使用的返回值。
发布于 2011-10-18 16:07:05
还有左边的三进制运算符:
$cond ? $var1 : $var2 = "the value";等同于:
if ($cond) {
$var1 = "the value";
} else {
$var2 = "the value";
}发布于 2011-10-18 01:48:58
$r = $r < $s ? $r : $s;
$r = $s if $r > $s;或
use List::Util qw( min );
$r = min($r, $s);或者:
sub min_inplace {
my $min_ref = \shift;
for (@_) { $$min_ref = $_ if $$min_ref > $_; }
}
min_inplace($r, $s);$r = $s if (defined $s);
$r = $s // $r;$r = $t; $r = $s if (defined $s);
$r = $s // $t;$r = !$s ? $s : $t;
$r = $s && $t;https://stackoverflow.com/questions/7796470
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