因此,我需要编写一个程序来提示输入文件名,然后打开该文件并通读该文件,查找以下形式的行:x-DSPAM-置信度: 0.8475我无法获得提取的值的总和,并计算行数并打印以显示给用户。
out_number = 'X-DSPAM-Confidence: 0.8475'
Num = 0.0
flag = 0
fileList = list()
fname = input('Enter the file name')
try:
fhand = open(fname)
except:
print('file cannot be opened:',fname)
for line in fhand:
fileList = line.split()
print(fileList)
for line in fileList:
if flag == 0:
pos = out_number.find(':')
Num = out_number[pos + 2:]
print (float(Num))发布于 2016-03-17 03:21:02
您的代码中有一个示例行,当您查看文件中的每一行时,计算的是示例行中的数字,而不是文件中的行。
所以,这就是我要做的:
import os
import sys
fname = input('Enter the file name: ')
if not os.path.isfile(fname):
print('file cannot be opened:', fname)
sys.exit(1)
prefix = 'X-DSPAM-Confidence: '
numbers = []
with open(fname) as infile:
for line in infile:
if not line.startswith(prefix): continue
num = float(line.split(":",1)[1])
print("found:", num)
numbers.append(num)
# now, `numbers` contains all the floating point numbers from the file
average = sum(numbers)/len(numbers)但我们可以让它更有效率:
import os
import sys
fname = input('Enter the file name: ')
if not os.path.isfile(fname):
print('file cannot be opened:', fname)
sys.exit(1)
prefix = 'X-DSPAM-Confidence: '
tot = 0
count = 0
with open(fname) as infile:
for line in infile:
if not line.startswith(prefix): continue
num = line.split(":",1)[1]
tot += num
count += 1
print("The average is:", tot/count)发布于 2016-03-17 03:34:09
尝尝这个
import re
pattern = re.compile("X-DSPAM-Confidence:\s(\d+.\d+)")
sum = 0.0
count = 0
fPath = input("file path: ")
with open('fPath', 'r') as f:
for line in f:
match = pattern.match(line)
if match is not None:
lineValue = match.group(1)
sum += float(lineValue)
count += 1
print ("The average is:", sum /count)发布于 2020-07-07 22:36:33
fname = input("Enter file name: ")
fh = open(fname)
count=0
x=0
for line in fh:
if not line.startswith("X-DSPAM-Confidence:") : continue
x=float(line.split(":")[1].rstrip())+x
count=count+1
output=x/count
print("Average spam confidence:",output)https://stackoverflow.com/questions/36044858
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