我正在使用Google places API,它会返回我所在位置的所有位置。然而,我只想让它返回一个“汽车维修”的类型,我想我差不多就有了,但我遗漏了一些东西,如果有人能把我引向正确的方向,那就太好了:)
我到目前为止的代码PlacPickerActivity
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.text.Html;
import android.view.View;
import android.widget.Button;
import android.widget.TextView;
import com.google.android.gms.common.GooglePlayServicesNotAvailableException;
import com.google.android.gms.common.GooglePlayServicesRepairableException;
import com.google.android.gms.location.places.Place;
import com.google.android.gms.location.places.ui.PlacePicker;
import com.google.android.gms.maps.model.LatLng;
import com.google.android.gms.maps.model.LatLngBounds;
public class PlacePickerActivity extends AppCompatActivity {
private static final int PLACE_PICKER_REQUEST = 1;
String url="https://maps.googleapis.com/maps/api/place/textsearch/json?type=car_repair&key=AIzaSyBKsTtLyMBQH8mhvbknJ4MvZwACotmeYO0";
private TextView mName;
private TextView mAddress;
private TextView mAttributions;
private TextView mNumber;
private static final LatLngBounds Sligo = new LatLngBounds(
new LatLng(54.27, -8.47), new LatLng(54.27, -8.47));
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_place_picker);
mName = (TextView) findViewById(R.id.textView);
mAddress = (TextView) findViewById(R.id.textView2);
mAttributions = (TextView) findViewById(R.id.textView3);
mNumber = (TextView) findViewById(R.id.textView4);
Button pickerButton = (Button) findViewById(R.id.pickerButton);
pickerButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
try {
PlacePicker.IntentBuilder intentBuilder =
new PlacePicker.IntentBuilder();
intentBuilder.setLatLngBounds(Sligo);
Intent intent = intentBuilder.build(PlacePickerActivity.this);
startActivityForResult(intent, PLACE_PICKER_REQUEST);
} catch (GooglePlayServicesRepairableException
| GooglePlayServicesNotAvailableException e) {
e.printStackTrace();
}
}
});
}
@Override
protected void onActivityResult(int requestCode,
int resultCode, Intent data) {
if (requestCode == PLACE_PICKER_REQUEST
&& resultCode == Activity.RESULT_OK) {
final Place place = PlacePicker.getPlace(this, data);
final CharSequence name = place.getName();
final CharSequence address = place.getAddress();
final CharSequence formatted_phone_number = place.getPhoneNumber();
String attributions = (String) place.getAttributions();
if (attributions == null) {
attributions = "";
}
mName.setText(name);
mAddress.setText(address);
mAttributions.setText(Html.fromHtml(attributions));
mNumber.setText(formatted_phone_number);
} else {
super.onActivityResult(requestCode, resultCode, data);
}
}
}清单文件
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.truiton.placepicker">
<uses-permission android:name="com.google.android.providers.gsf.permission.READ_GSERVICES"/>
<uses-permission android:name="android.permission.INTERNET"/>
<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION"/>
<application
android:allowBackup="true"
android:icon="@mipmap/ic_launcher"
android:label="@string/app_name"
android:theme="@style/AppTheme">
<meta-data
android:name="com.google.android.gms.version"
android:value="@integer/google_play_services_version"/>
<meta-data
android:name="com.google.android.geo.API_KEY"
android:value="AIzaSyBKsTtLyMBQH8mhvbknJ4MvZwACotmeYO0"/>
<activity
android:name=".PlacePickerActivity"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN"/>
<category android:name="android.intent.category.LAUNCHER"/>
</intent-filter>
</activity>
</application>
</manifest>当我在PC上的浏览器中输入URL时,它会返回我所在区域的所有类型"car_repair“,因此我的API键可以正常工作

发布于 2016-03-19 23:01:17
尝试使用类似如下的查询: Location is in format latitude,longitude...and小心是"types“而不是type。
https://maps.googleapis.com/maps/api/place/nearbysearch/json?location=54.27,-8.47&radius=1000&types=car_repair&key=AddYourOwnKeyHere发布于 2016-03-19 23:23:35
因为此API返回作用域中的place类型。有一种方法可能会改善结果,但仍然不是最优的,那就是setLatLngBounds.The link is https://developers.google.com/android/reference/com/google/android/gms/location/places/ui/PlacePicker.IntentBuilder#public-method-summary我以前试过这个接口,发现它在某种程度上完全是一团糟。例如,如果您要查找大学内部的餐厅,此接口不仅会返回餐厅,还会返回许多其他类型,如University。设置一个界限可能是好的,但如果你只使用API,仍然会得到恼人的结果。如果你只想要car-repair的类型,我建议你写一个过滤器来过滤其他类型,只保留汽车维修类型和相关信息。
发布于 2016-03-20 15:26:12
这是我为你准备的,希望对你有所帮助
// A class to store your results
public class Place {
private String icon;
private Double latitude;
public void setIcon(String icon) {
this.icon=icon;
}
public void setLatitude(Double latitude) {
this.latitude=latitude;
}
// .....
}
// Utility class to keep things simple
public class Functions {
public static JSONObject convertInputStreamToJSONObject(InputStream inputStream)
throws JSONException, IOException
{
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(inputStream));
String line = "";
String result = "";
while ((line = bufferedReader.readLine()) != null)
result += line;
inputStream.close();
return new JSONObject(result);
}
public static ArrayList<Place> parsePlacesFromJson(JSONObject datos) throws JSONException {
List<Place> placesList = new ArrayList<>();
// in your case this must be "results" I think
final int LIST_LENGTH = datos.getJSONArray("results").length();
//final int LIST_LENGTH = datos.getJSONArray("nameOfTheJsonMainArray").length();
Log.d("Length", String.valueOf(LIST_LENGTH));
// For every element in the list
for(int i = 0; i < LIST_LENGTH; i++) {
// Instance of a new Place
Place place = new Place();
// Get data as needed, this represents one place
JSONObject obj = datos.getJSONArray("results").getJSONObject(i);
Double latitude = obj.getJSONObject("geometry").getJSONObject("location").getDouble("lat");
String icon = obj.getString("icon");
place.setLatitude(latitude);
place.setIcon(icon);
//....
placesList.add(place)
}
return placesList;
}
}
// The google places reader class
public class ApiReader {
private static final String TAG = "API_READER";
Context context;
View v;
public ApiReader(Context context, View v) {
this.context = context;
this.v = v;
}
private static final String APIKEY = "yourkeyhere";
private static String ENDPOINT =
"https://maps.googleapis.com/maps/api/place/nearbysearch/json?location=54.27,-8.47&radius=1000&types=car_repair&key=%s";
// Method to be called
public void getCarRepairs() throws IOException {
URL url = new URL(String.format(ENDPOINT, APIKEY));
new GetPlaces().execute(url);
}
// Inner asyctask class
private class GetPlaces extends AsyncTask<URL, Integer, List<Place>> {
List<Place> lista;
@Override
protected List<Place> doInBackground(URL... params) {
JSONObject datos;
URL url = params[0];
HttpURLConnection urlConnection = null;
try {
urlConnection = (HttpURLConnection) url.openConnection();
InputStream in = new BufferedInputStream(urlConnection.getInputStream());
datos = Functions.convertInputStreamToJSONObject(in);
Log.i(TAG, datos.toString());
// De los datos obtenemos un objeto Place
lista = Functions.parsePlacesFromJson(datos);
Log.i(TAG, "" + lista.toString());
Log.i(TAG, "Went into try was OK.");
} catch (Exception e) {
Log.e(TAG, e.toString());
Log.i(TAG, "Went into catch");
} finally {
urlConnection.disconnect();
Log.i(TAG, "Went into finally, urlConnection disconnected.");
}
return lista;
}
// This method it gets what the "doInBackGround" returns
protected void onPostExecute(List<Place> placesList) {
if(placesList != null) {
// Do whatever with the list of places
//Functions.updateView(v, placesList);
}
}
}
}
// And to make things work in yout activity just do like this
ApiReader api = new ApiReader(this, findViewById(R.id.mainLayout));
try {
api.getCarRepairs();
} catch (IOException e) {
e.printStackTrace();
}享受吧!!
https://stackoverflow.com/questions/36060373
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