AsyncDisplayKit - ASButton大小

Question

Table Cell

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我正在学习使用Asyncdisplaykit。我的结果如下图所示。但我不知道如何约束按钮等于Screen.width/3，它的自动约束等于图像宽度。这是我的代码

    let controlStack = ASStackLayoutSpec(direction: ASStackLayoutDirection.Horizontal, spacing: 3.0, justifyContent: ASStackLayoutJustifyContent.Center, alignItems: ASStackLayoutAlignItems.Center, children: [self.mFavoriteButton, self.mCommentButton, self.mShareButton])
    controlStack.spacingAfter = 3.0
    controlStack.spacingBefore = 3.0

    let insetDateLayout = ASInsetLayoutSpec(insets: UIEdgeInsets(top: 10, left: self.frame.size.width - 100, bottom: 0, right: 0), child: self.mDateTimeNode)
    let imageLayout = ASStaticLayoutSpec(children: [imagePlace, insetDateLayout])


    return ASStackLayoutSpec(direction: .Vertical, spacing: 3.0, justifyContent: ASStackLayoutJustifyContent.Start, alignItems: ASStackLayoutAlignItems.Center, children:[imageLayout, self.mMessageNode, controlStack])

Answer 1

尝试将ASStackLayoutAlignItems.Center更改为ASStackLayoutAlignItems.Stretch。并尝试为按钮启用增长约束(需要测试它)：

self.mFavoriteButton.flexGrow = true;
self.mCommentButton.flexGrow = true;
self.mShareButton.flexGrow = true;

Answer 2

如果你能解决这个问题，请回复！

通常，您希望使用相对大小为0.33的flexBasis来执行1/3的操作。查看Web / CSS flexbox上的文档以获取flexbasis的示例。