Pywinauto和Installshield

Question

我的应用程序是使用InstallShield打包的。执行exe时发生的第一件事是提取msi文件；这大约需要10秒。

在msi提取完成之前，我无法找到我的主窗口，所以我使用time.sleep。然后我查找并找到我的窗口的句柄。但是对app.window_(handle=1234).Wait("enabled"，timeout=25，retry_interval=0.5)的调用失败了，出现了这些错误消息。

*C:\python32>python test.py
| [2558122] |
Traceback (most recent call last):
  File "test.py", line 16, in <module>
    dlg = app.Window_(handle=hwnd).Wait("enabled", timeout=25, retry_interval=0.
5)
  File "C:\python32\lib\site-packages\pywinauto\application.py", line 380, in Wa
it
    WaitUntil(timeout, retry_interval, lambda: self.__check_all_conditions(check
_method_names))
  File "C:\python32\lib\site-packages\pywinauto\timings.py", line 292, in WaitUn
til
    func_val = func(*args)
  File "C:\python32\lib\site-packages\pywinauto\application.py", line 380, in <l
ambda>
    WaitUntil(timeout, retry_interval, lambda: self.__check_all_conditions(check
_method_names))
  File "C:\python32\lib\site-packages\pywinauto\application.py", line 337, in __
check_all_conditions
    check = getattr(self, check_name)
  File "C:\python32\lib\site-packages\pywinauto\application.py", line 252, in __
getattr__
    ctrls = _resolve_control(self.criteria)
  File "C:\python32\lib\site-packages\pywinauto\application.py", line 755, in _r
esolve_control
    criteria)
  File "C:\python32\lib\site-packages\pywinauto\timings.py", line 356, in WaitUn
tilPasses
    func_val = func(*args)
  File "C:\python32\lib\site-packages\pywinauto\application.py", line 522, in _g
et_ctrl
    findwindows.find_window(**criteria[0]))
  File "C:\python32\lib\site-packages\pywinauto\controls\HwndWrapper.py", line 1
80, in __new__
    new_class = cls.FindWrapper(handle)
  File "C:\python32\lib\site-packages\pywinauto\controls\HwndWrapper.py", line 1
12, in FindWrapper
    class_name = handleprops.classname(handle)
  File "C:\python32\lib\site-packages\pywinauto\handleprops.py", line 94, in cla
ssname
    win32functions.GetClassName (handle, ctypes.byref(class_name), 256)
ctypes.ArgumentError: argument 1: <class 'TypeError'>: Don't know how to convert
 parameter 1*

这就是代码。我是一个有经验的程序员，但是是一个Python新手。我花了一整天的时间，用谷歌搜索了我的大脑，尝试了我能想到的所有方法。提前谢谢。

from pywinauto import application
from pywinauto import findwindows

app = application.Application()

app.start("MyInstallShieldApp.exe")

time.sleep(15)

hwnd=findwindows.find_windows(title=u"InstallShield Wizard", class_name="MsiDialogCloseClass")
print ("|", str(hwnd), "|")
dlg = app.Window_(handle=hwnd).Wait("enabled", timeout=25, retry_interval=0.5)

Answer 1

hwnd中的问题是一个列表，但是handle=hwnd需要一个整数。您应该使用find_window而不是find_windows，或者只使用hwnd中的第一个句柄，例如

hwnd = findwindows.find_windows(... dlg = app.Window_(handle=hwnd[0])...

对于你来说，使用pywinauto的SWAPY - UI检查器和代码生成器也会很有用。

Answer 2

这个问题已经提了一年了，但希望它能帮助其他处于同样境地的人。我最初有一些类似于OP的东西，但完全迷惑了，因为我认为它会像pywinauto github存储库中提供的7zip installation example一样简单。然而，我发现实际的安装是在第二个过程中打开的，这与使用Application().start()打开应用程序以同时启动和挂钩程序的观点相去甚远。

我所做的是使用Windows SDK中的Inspect程序来定位元素的名称，以及在InstallShield完成提取.msi文件后保存它们的窗口。我没有使用start()打开InstallShield可执行文件，而是使用subprocess模块的popen()函数打开安装程序，然后在通过InstallShield解压后使用Application().connect()挂接到安装程序。下面是我为获得此功能所做的粗略版本，将我的发现与示例、文档和操作混合在一起：

import time
import subprocess
from pywinauto import application

# Open the module via Popen 
# I tried using run() first but that prevented the click for reasons unknown
subprocess.Popen(r"C:\Users\fixer446\My Documents\InstallationFiles\Setup.exe")

# Let InstallShield extract the files and the installer load completely
time.sleep(15)

# Hook onto the newly opened setup window
app = application.Application().connect(title="Setup.WindowName", class_name="MsiDialogCloseClass")

# Work with the window and the controls within as advertised in pywinauto
# You may have to play around with this a little
installer = app["Setup.WindowName"]
installer["Next >"].Wait("enabled")
installer["Next >"].Click()

希望这能有所帮助。

Answer 3

app.Window_(...)可以接受与find_windows(...)相同的参数。是啊，现在文档里还没有高亮显示。但是代码可能会更短：

from pywinauto import application
from pywinauto import findwindows

app = application.Application()
app.start("MyInstallShieldApp.exe")

# the dialog may not exist yet here
dlg_spec = app.Window_(title=u"InstallShield Wizard", class_name="MsiDialogCloseClass")

# after this line the dialog exists or exception is raised
dlg = dlg_spec.Wait("enabled", timeout=25, retry_interval=0.5)

# dlg is a DialogWrapper object (for really existing dialog)

您可以在this answer中阅读有关2级WindowSpecification概念的更多详细说明。

我将把它与即将到来的pywinauto 0.6.0 (稍晚一点)一起移到文档中。