解析Google Shopping Json搜索结果

Question

在尝试了几个星期后，在这里找到了无数的例子，似乎遍及整个网络，我被难住了。我可以从Google Shopping检索到所需的搜索结果：

{ "items": [  {   "product": {
"title": "The Doctor's BrushPicks Toothpicks 250 Pack",
"brand": "The Doctor's"  } } ] }

我的问题是，我有一个字符串中的数据，我如何提取两个值(标题，品牌)，以便在程序中的其他地方使用它们？

下面是有问题的类:公共类HttpExample扩展了Activity {

TextView httpStuff;
DefaultHttpClient client;
JSONObject json;


final static String URL = "https://www.googleapis.com/shopping/search..."; 

   @Override
   protected void onCreate(Bundle savedInstanceState) {
      super.onCreate(savedInstanceState);
    setContentView(R.layout.httpex);
    httpStuff = (TextView) findViewById(R.id.tvHttp);
    client = new DefaultHttpClient();
    new Read().execute("items");

}

public JSONObject products(String upc)  throws ClientProtocolException, IOException, JSONException {
    StringBuilder url = new StringBuilder(URL);
    url.append(upc);

    HttpGet get = new HttpGet(url.toString());
    HttpResponse r = client.execute(get);
    int status = r.getStatusLine().getStatusCode();
    if (status == 200) {
        HttpEntity e = r.getEntity();
        String data = EntityUtils.toString(e);
        JSONObject timeline = new JSONObject(data);
        return timeline;
    } else {
        Toast.makeText(HttpExample.this, "error", Toast.LENGTH_SHORT);
        return null;
    }
}

public class Read extends AsyncTask<String, Integer, String> {

    @Override
    protected String doInBackground(String... params) {
        // TODO Auto-generated method stub
        try {
            String upc = ExportMenuActivity.upc;
            json = products(upc);
            return json.getString(params[0]);
        } catch (ClientProtocolException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        return null;
    }

@Override
protected void onPostExecute(String result){
    httpStuff.setText(result);
}
}

}

HttpStuff.setText(结果)的输出：

[{"product":{"brand":"The Doctor's, "title":"The Doctor's..."}}]

Answer 1

一个适用于所有Android版本的解决方案如下所示：

JSONObject products = products(jsonStr);
JSONArray itemArray = products.getJSONArray("items");
for(int i=0; i<itemArray.length(); i++) {
  if(itemArray.isNull(i) == false) {
    JSONObject item = itemArray.getJSONObject(i);
    String title = item.getString("title");
    String brand = item.getString("brand");
  }
}

JsonReader很不错，但只在API10和更高版本中可用。所以它可能对你有用，也可能对你没用。

Answer 2

您应该使用JsonReader来读取json字符串。它非常简单，并且有很好的文档和非常好的示例..here