我想用一个变量列表自动化一个python函数。

Question

import sys

print('Do you want a cup of tea?')

user_input_tea = input().lower()

if user_input_tea == 'yes':
    print("You feel the thirst for a nice cup of tea, now it's time to make it.")
else:
    print('You feel a cup of tea is not for you.')
    sys.exit(0)

equipment = []

def equipment_find(item):
    if item == str(item):
        print("You have acquired the " + str(item) + " , now it's time to proceed.")
        equipment.append(item)
        print(equipment)
    else:
        print("You did not enter: " + str(item))

        while True:
            print("Please input: " str(item))
            if item == str(item):
                equipment.append(item)
                print(equipment)
                break

print("You are going to need a kettle for this tea making process, please input kettle to acquire the kettle")

kettle = input().lower()

equipment_find(kettle)

上面的代码就是我所拥有的。我想要它，所以我已经有了用户输入的变量，有没有什么我可以用for循环或其他东西自动触发的函数。

Answer 1

这里有一个我认为你想要实现的简化示例。我们指定了所需配料的列表，并要求用户输入项目，直到他们拥有所有项目。我在比较过程中使用set()，因为我们不关心条目输入的顺序。

requiredItemsList = ['kettle', 'water', 'spoon', 'sugar']
enteredItmesList = []

print("You feel the thirst for a nice cup of tea, now it's time to make it.")

while set(requiredItemsList) != set(enteredItmesList):
    item = input('Enter an item: ')
    if item in requiredItemsList and item not in enteredItmesList:
        print('You have acquired the', item, ", now it's time to proceed.")
        enteredItmesList.append(item)
    else:
        print('The item you entered is not valid. Please try again.')

print('You have aquired all needed items!')
print(enteredItmesList)