我有一张这样的桌子;
jobID - jobTitle - jobCreatedDate
我想让访问者可以在Job表中进行搜索,并像这样按分组列出它,我只想用一个SQL查询来做到这一点:
Date Added
- AnyTime (20)
- 1 day ago (5)
- 2-7 days ago (2)
- 8-14 days ago (0)
- 15-30 days ago (7)我尝试了Group By "jobCreatedDate“,但没有成功,我不能理解必要查询的逻辑。
下面是我想要做的一个例子:

谢谢你的帮助。
发布于 2011-08-08 08:48:12
您需要找出today和字段JobCreated之间的日期差异。然后根据值天数的差异,您需要将输出相应地分类到不同的类别中,以满足您的需求。
我希望这就是你要找的。
SELECT SUM(1) AS [AnyTime]
, SUM(CASE WHEN DayCount = 1 THEN 1 ELSE 0 END) AS [1 day ago]
, SUM(CASE WHEN DayCount BETWEEN 2 AND 7 THEN 1 ELSE 0 END) AS [2-7 days ago]
, SUM(CASE WHEN DayCount BETWEEN 8 AND 14 THEN 1 ELSE 0 END) AS [8-14 days ago]
, SUM(CASE WHEN DayCount BETWEEN 15 AND 30 THEN 1 ELSE 0 END) AS [15-30 days ago]
FROM
(
SELECT JobID
, DATEDIFF(d, JobCreatedDate, GETDATE()) AS DayCount
FROM dbo.Jobs
) Jobs屏幕截图显示了示例数据和查询输出。

发布于 2011-08-08 08:41:43
使用DATEADD tsql方法。
Select ...
From [Table]
Where JobCreatedDate between DATEADD(dd, @NumDays, GetDate()) and GetDate()在这个查询中,@NumDays是一个参数,表示从当前日期减去的天数。确保将负数传递给查询。如果您试图创建非包含范围,则需要使用两个DATEADD调用,并将两个参数传递给查询。
我误解了你想要做的事情。这可能不是最优雅的解决方案,但是您可以使用联合查询来实现您的目标。
Select sum(OneDay) as OneDay, sum(SevenDays) as SevenDays
From
(select 1 as OneDay, 0 as SevenDays
From [table]
Where JobCreatedDate between DATEADD(dd, -1, GetDate()) and GetDate())
UNION
(select 0 as OneDay, 1 as SevenDays
From[table]
Where JobCreatedDate between DATEADD(dd, -7, GetDate()) and DATEADD(dd, -2, GetDate()))https://stackoverflow.com/questions/6976800
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