为什么我的画布上的MouseLeftButtonUp不能在我的WPF应用程序中触发?下面是XAML:
<Grid Height="300" Width="400">
<Canvas Name="canvas" MouseMove="canvas_MouseMove" MouseLeftButtonUp="canvas_MouseLeftButtonUp" Background="LightGray"/>
</Grid>和代码:
private bool hasClicked = false;
public Window1()
{
InitializeComponent();
}
private void canvas_MouseMove(object sender, MouseEventArgs e)
{
if (!this.hasClicked)
{
this.Cursor = Cursors.None;
this.canvas.Children.Clear();
this.insertRectangle(false);
}
}
private void insertRectangle(bool filled)
{
Rectangle rect = createRect(filled);
Point pos = Mouse.GetPosition(this.canvas);
Canvas.SetLeft(rect, pos.X);
Canvas.SetTop(rect, pos.Y);
this.canvas.Children.Add(rect);
}
private Rectangle createRect(bool fill)
{
Rectangle rect = new Rectangle();
rect.Height = 50;
rect.Width = 120;
if (fill)
{
rect.Fill = new SolidColorBrush(Colors.Green);
}
else
{
rect.Stroke = new SolidColorBrush(Colors.Green);
}
return rect;
}
private void canvas_MouseLeftButtonUp(object sender, MouseButtonEventArgs e)
{
this.hasClicked = true;
this.insertRectangle(true);
this.Cursor = Cursors.Arrow;
}编辑:我尝试在画布上添加背景色,但事件仍未触发。似乎MouseMove以某种方式覆盖了MouseLeftButtonUp。
Edit2:如果移除MouseMove事件,mouseLeftButtonUp将触发。
Edit3:更大的代码示例。在insertRectangle方法中,如果我使用
Canvas.SetTop(rect, 50);
instead of
Canvas.SetTop(rect, pos.Y);事件触发得很好。
发布于 2011-07-19 22:24:59
通过不清除画布,而是在mouseMove方法中移动预览矩形,解决了这个问题。
发布于 2011-07-16 15:34:42
如果你没有在画布上设置一个Background,它似乎不会注意到你的鼠标事件。
尝试:
<Grid>
<Canvas Name="canvas"
MouseMove="canvas_MouseMove"
MouseLeftButtonUp="canvas_MouseLeftButtonUp"
Background="White" />
</Grid>https://stackoverflow.com/questions/6716029
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