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按顺序排列的数字分组
EN

Stack Overflow用户
提问于 2011-06-30 22:58:06
回答 5查看 4.1K关注 0票数 4

我有一些这样的数据:

代码语言:javascript
复制
row    id
1      1
2      36
3      37
4      38
5      50
6      51

我想查询它如下所示:

代码语言:javascript
复制
 row    id    group
 1      1     1
 2      36    2
 3      37    2
 4      38    2
 5      50    3
 6      51    3

..。这样我就可以根据数字连续的位置进行分组。

此外,循环/游标是不可能的,因为我正在处理相当大的数据集,谢谢。

EN

回答 5

Stack Overflow用户

回答已采纳

发布于 2011-06-30 23:19:59

代码语言:javascript
复制
create table #temp
(
    IDUnique int Identity(1,1),
    ID int, 
    grp int
)


Insert into #temp(ID) Values(1)
Insert into #temp(ID) Values(36)
Insert into #temp(ID) Values(37)
Insert into #temp(ID) Values(38)
Insert into #temp(ID) Values(50)
Insert into #temp(ID) Values(51)

declare @IDUnique int
declare @PreviousUnique int
declare @ID int
declare @grp int
declare @Previous int
declare @Row int

DECLARE @getAccountID CURSOR SET @getAccountID = CURSOR FOR SELECT Row_Number() Over(Order by IDUnique) Row, IDUnique, ID  From #temp
OPEN @getAccountID
FETCH NEXT FROM @getAccountID INTO @Row, @IDUnique, @ID 
WHILE @@FETCH_STATUS = 0
BEGIN
    IF(@Row = 1)
    Begin
        update #temp set grp = 1 Where IDUnique = @IDUnique
        set @Previous = @ID
        set @grp = 1
    End
    Else If (@Previous + 1 = @ID)
    Begin
        update #temp set grp = @grp Where IDUnique = @IDUnique
        set @Previous = @ID
    End
    Else
    Begin
        set @Previous = @ID
        set @grp = @grp + 1
        update #temp set grp = @grp Where IDUnique = @IDUnique
    End
    FETCH NEXT FROM @getAccountID INTO @Row, @IDUnique, @ID
END
CLOSE @getAccountID
DEALLOCATE @getAccountID

Select * from #temp
Drop Table #temp
票数 1
EN

Stack Overflow用户

发布于 2011-06-30 23:15:06

代码语言:javascript
复制
;WITH firstrows AS
(
    SELECT id, ROW_NUMBER() OVER (ORDER BY id) groupid
    FROM Table1 a
    WHERE id - 1 NOT IN (SELECT b.id FROM Table1 b)
)
SELECT id, 
    (
        SELECT MAX(b.groupid)
        FROM firstrows b
        WHERE b.id <= a.id
    ) groupid
FROM Table1 a
票数 4
EN

Stack Overflow用户

发布于 2011-06-30 23:16:23

代码语言:javascript
复制
with
  data(row, id) as (
    select * 
    from (
      values
       (1,1)
      ,(2,36)
      ,(3,37)
      ,(4,38)
      ,(5,50)
      ,(6,51)
    ) as foo(row, id)
  ),
  anchor(row, id) as (
    select row, id
    from data d1
    where not exists(select 0 from data d2 where d2.id = d1.id - 1)
  )
select d1.*, dense_rank() over(order by foo.id) as thegroup
from
  data d1
  cross apply (select max(id) from anchor where anchor.id <= d1.id) as foo(id)
order by
  d1.row
  ;
票数 4
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/6536780

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