IFTweetLabel RegexKitLite打开UIWebView

Question

我使用的是IFTweetLabel，它能识别链接，但我很难用IFTweetLabel创建的按钮打开一个网页视图。我正在运行NSLog，可以清楚地看到它正在理解每个链接，当按钮被按下时，但由于某种原因，它不会打开网址。

下面是我用来显示视图和在webView....which中加载字符串的代码，除了加载webview之外，所有这些都是有效的。

如有任何建议，我们将不胜感激！谢谢!

- (void)handleTweetNotification:(NSNotification *)notification

{
[UIView beginAnimations:@"animateView" context:nil];
[UIView setAnimationDuration:1.0];

CGRect viewFrame = [MainwebView frame];
viewFrame.origin.x = 220;
MainwebView.frame = viewFrame;        

MainwebView.alpha = 1.0; 
web.alpha = 1.0;

MainwebView.layer.shadowColor = [[UIColor blackColor] CGColor];
MainwebView.layer.shadowOffset = CGSizeMake(1.0f, 1.0f);
MainwebView.layer.shadowRadius = 8.0f;
MainwebView.layer.shadowOpacity = 1.0f;     



[self.view addSubview:MainwebView];
[UIView commitAnimations];
[web loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:tweetLabel.text]]]; 

NSLog(@"handleTweetNotification: WTF notification = %@", notification);
}

Answer 1

以下是我的代码，它们应该工作得很好，但也应该进行一些清理：

    - (void)handleTweetNotification:(NSNotification *)notification {    

    unichar theChar = [(NSString *)notification.object characterAtIndex:0];
    NSString *theString = (NSString *)notification.object;


    if ( [[NSString stringWithCharacters:&theChar length:1] isEqualToString:@"#"]) {
        DLog(@"This is a hashtag");
        theString = [theString stringByReplacingOccurrencesOfString:@"#" withString:@"%23"];
        NSURL *hashtagURL = [NSURL URLWithString:[NSString stringWithFormat:@"https://twitter.com/#!/search?q=%@", theString]];
        WebViewController *theWebVC = [[WebViewController alloc] init];
        theWebVC.request = [NSURLRequest requestWithURL:hashtagURL];
        UINavigationController *theNavigationVC = [[UINavigationController alloc] initWithRootViewController:theWebVC];
        [self presentModalViewController:theNavigationVC animated:YES];

    }

    if ( [[NSString stringWithCharacters:&theChar length:1] isEqualToString:@"@"]) {
        DLog(@"This is a Mention");
        theString = [theString stringByReplacingOccurrencesOfString:@"@" withString:@""];
        NSURL *mentionURL = [NSURL URLWithString:[NSString stringWithFormat:@"https://twitter.com/%@", theString]];
        WebViewController *theWebVC = [[WebViewController alloc] init];
        theWebVC.request = [NSURLRequest requestWithURL:mentionURL];
        UINavigationController *theNavigationVC = [[UINavigationController alloc] initWithRootViewController:theWebVC];
        [self presentModalViewController:theNavigationVC animated:YES];

    }
    if ( [[NSString stringWithCharacters:&theChar length:1] isEqualToString:@"h"]) {
        DLog(@"This is a hyperlink");
        theString = [[theString componentsSeparatedByString: @"\n"] objectAtIndex:0];
        NSURL *hyperlinkURL = [NSURL URLWithString:[NSString stringWithFormat:@"%@", theString]];
        WebViewController *theWebVC = [[WebViewController alloc] init];
        theWebVC.request = [NSURLRequest requestWithURL:hyperlinkURL];
        UINavigationController *theNavigationVC = [[UINavigationController alloc] initWithRootViewController:theWebVC];
        [self presentModalViewController:theNavigationVC animated:YES];
    }
}

Answer 2

用户单击的字符串将传递给此方法，并可通过使用通知对象找到。您在代码中所做的就是将tweetLabel中的所有文本传递给webview。由于这不是一个URL，你的应用程序将崩溃。改用这个：[web loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:[notification object]]]];

您也可以首先对通知对象执行NSLog操作，以确保它是一个URL。