Android -获取昵称和昵称类型

Question

我已经尝试了几个小时来获取联系人的昵称，但仍然不能让他们工作，我被告知他们在一个与电话号码等不同的表中。但我不知道如何访问它们。

我能找到的最接近的是这个..

Cursor cursor = context.getContentResolver().query(ContactsContract.Contacts.CONTENT_URI, null, ContactsContract.Contacts._ID +" = ?", new String[]{String.valueOf(recordId)}, null);
    while (cursor.moveToNext()) {
       Cursor nickname = context.getContentResolver().query( ContactsContract.Data.CONTENT_URI, null, ContactsContract.CommonDataKinds.Nickname.CONTACT_ID +" = "+ recordId, null, null); 
       while (nickname.moveToNext()) { 
           try {
           String nicknameName = nickname.getString(nickname.getColumnIndex(ContactsContract.CommonDataKinds.Nickname.NAME));
           String nicknameType = nickname.getString(nickname.getColumnIndex(ContactsContract.CommonDataKinds.Nickname.TYPE));

           switch (Integer.valueOf(nicknameType)) {
           case 1: nicknameType = "TYPE_HOME"; break;
           }
           list.add(new KeyValue("Nickname:" + nicknameType, nicknameName));
           } catch (Exception e) { continue; }
       }
       nickname.close();
    }

这将获得联系人的所有数据以及类型，例如：Thomas Owers 1这很好，但它没有给我数据，所以它给出了电子邮件，电话，姓名，昵称，但我无法区分它们。

任何帮助都将非常感谢，谢谢！:)

Answer 1

我在网上搜索了几个小时后才找到这个昵称……

ArrayList<KeyValue> list = new ArrayList<KeyValue>();

    Cursor cursor = context.getContentResolver().query(ContactsContract.Contacts.CONTENT_URI, null, ContactsContract.Contacts._ID +" = ?", new String[]{String.valueOf(recordId)}, null);
    while (cursor.moveToNext()) {
       String where = ContactsContract.Data.CONTACT_ID + " = ? AND " + ContactsContract.Data.MIMETYPE + " = ?";
       String[] params = new String[] {String.valueOf(recordId), ContactsContract.CommonDataKinds.Nickname.CONTENT_ITEM_TYPE};
       Cursor nickname = context.getContentResolver().query(ContactsContract.Data.CONTENT_URI, null, where, params, null); 
       while (nickname.moveToNext()) { 
            String nicknameName = nickname.getString(nickname.getColumnIndex(ContactsContract.CommonDataKinds.Nickname.NAME));
            String nicknameType = nickname.getString(nickname.getColumnIndex(ContactsContract.CommonDataKinds.Nickname.TYPE));
            switch (Integer.valueOf(nicknameType)) {
            case 1: nicknameType = "Default"; break;
            case 2: nicknameType = "OtherName"; break;
            case 3: nicknameType = "MaidenName"; break;
            case 4: nicknameType = "ShortName"; break;
            case 5: nicknameType = "Initials"; break;
            }
            list.add(new KeyValue("Nickname:" + nicknameType, nicknameName));
       }
       nickname.close();
    }
    return list;

此代码获得昵称！:)

Answer 2

不要获取所有数据。仅使用投影获取所需数据

String[] proj ={ContactsContract.CommonDataKinds.Nickname.NAME, ContactsContract.CommonDataKinds.Nickname.TYPE};

Cursor nickname = getContentResolver().query( ContactsContract.Data.CONTENT_URI, proj,ContactsContract.CommonDataKinds.Nickname.CONTACT_ID +" = "+ recordId, null, null);