blocks|key|4140204|text|这是黑客等级挑战The+Blunder的解决方案(MySQL)|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4140205|SELECT+CEIL((AVG(salary))+-+(AVG(REPLACE(salary,+'0',+''))))+AS+avg_salary+FROM+employees;|code-block|syntax|javascript|4140206|4140207|REPLACE()：用于从工资中去掉0。|unordered-list-item|4140208|AVG()：用于计算平均工资。|4140209|CEIL()：用于获取下一个舍入的整数。|4140210|4140211|entityMap|0|LINK|mutability|MUTABLE|url|https://www.hackerrank.com/challenges/the-blunder/problem^0|8|B|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Z|8|@]|9|@$A|10|B|11|1|12]]|C|$]]|$1|D|3|E|5|F|7|13|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|14|8|@]|9|@]|C|$]]|$1|J|3|K|5|L|7|15|8|@]|9|@]|C|$]]|$1|M|3|N|5|L|7|16|8|@]|9|@]|C|$]]|$1|O|3|P|5|L|7|17|8|@]|9|@]|C|$]]|$1|Q|3|-4|5|6|7|18|8|@]|9|@]|C|$]]|$1|R|3|-4|5|6|7|19|8|@]|9|@]|C|$]]]|S|$T|$5|U|V|W|C|$X|Y]]]]

Here is the solution (MySQL) for Hackerrank challenge <a href="https://www.hackerrank.com/challenges/the-blunder/problem" rel="noreferrer">The Blunder</a>

<pre><code>SELECT CEIL((AVG(salary)) - (AVG(REPLACE(salary, '0', '')))) AS avg_salary FROM employees;
</code></pre>

<ul>
<li>REPLACE() : used to remove 0 from salary.</li>
<li>AVG() : used to calculate average salary.</li>
<li>CEIL() : used to get next rounded integer.</li>
</ul>

blocks|key|4140043|text|++REPLACE('0349010330',+'0',+'');|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4140044|这也是可行的|unstyled|4140045|++REPLACE('0349010330',+'0');|4140046|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code> REPLACE('0349010330', '0', '');
</code></pre>

this also work

<pre><code> REPLACE('0349010330', '0');
</code></pre>

blocks|key|5557643|text|Oracle/PLSQL|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5557644|SELECT+TO_NUMBER(REPLACE(TO_CHAR(0349010330),'0',''))+FROM+DUAL;|code-block|syntax|javascript|5557645|MySQL|5557646|SELECT+CONVERT(REPLACE(STR(0349010330),'0',''),INTEGER)+FROM+DUAL;|5557647|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Oracle/PLSQL

<pre><code>SELECT TO_NUMBER(REPLACE(TO_CHAR(0349010330),'0','')) FROM DUAL;
</code></pre>

MySQL

<pre><code>SELECT CONVERT(REPLACE(STR(0349010330),'0',''),INTEGER) FROM DUAL;
</code></pre>

blocks|key|5557952|text|无需将其转换为字符串即可使用replace|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5557953|MySQL解决方案|offset|length|style|BOLD|5557954|SELECT+CEIL(AVG(SALARY)-AVG(REPLACE(SALARY,"0","")))+FROM+EMPLOYEES+;+|code-block|syntax|javascript|5557955|entityMap^0|0|0|9|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@$D|Q|E|R|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|S|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

No need to convert it into string to use replace
MySQL solution
<pre><code>SELECT CEIL(AVG(SALARY)-AVG(REPLACE(SALARY,&quot;0&quot;,&quot;&quot;))) FROM EMPLOYEES ; 
</code></pre>

blocks|key|5557653|text|HackerRank+Problem+link|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|5557654|解决方案在这里->|5557655|`SELECT+ROUND(AVG(SALARY)-AVG(TO_NUMBER(REPLACE(TO_CHAR(SALARY),'0')))%2B.5,0)+FROM+EMPLOYEES;`|code-block|syntax|javascript|5557656|entityMap|0|LINK|mutability|MUTABLE|url|https://www.hackerrank.com/challenges/the-blunder/problem^0|0|N|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|6|7|W|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|X|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

<a href="https://www.hackerrank.com/challenges/the-blunder/problem" rel="noreferrer">HackerRank Problem link</a>

Solution Here ->

<pre><code>`SELECT ROUND(AVG(SALARY)-AVG(TO_NUMBER(REPLACE(TO_CHAR(SALARY),'0')))+.5,0) FROM EMPLOYEES;`
</code></pre>

blocks|key|4140151|text|MYSQL：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4140152|REPLACE('0349010330'，'0'，'')|4140153|这将用空字符串替换字符串中的所有O。|4140154|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|I|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|J|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|G|$]]

MYSQL:

REPLACE('0349010330', '0', '')

This will replace all the Os in the string with an empty string.

blocks|key|4140389|text|针对SQL+Server的HakerRank解决方案|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4140390|SELECT+CEILING(AVG(SALARY))-+CEILING(AVG(CAST(REPLACE(SALARY,'0','')AS+INT)))+%2B1+FROM+EMPLOYEES;|code-block|syntax|javascript|4140391|我不知道为什么最后需要'%2B1‘才能得到正确的答案。|4140392|entityMap|0|LINK|mutability|MUTABLE|url|https://www.hackerrank.com/challenges/the-blunder/problem?utm_campaign=challenge-recommendation&utm_medium=email&utm_source=30-day-campaign^0|D|9|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]]|C|$]]|$1|D|3|E|5|F|7|W|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|X|8|@]|9|@]|C|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]]]

<a href="https://www.hackerrank.com/challenges/the-blunder/problem?utm_campaign=challenge-recommendation&amp;utm_medium=email&amp;utm_source=30-day-campaign" rel="nofollow noreferrer">HakerRank</a> solution for SQL Server
<pre><code>SELECT CEILING(AVG(SALARY))- CEILING(AVG(CAST(REPLACE(SALARY,'0','')AS INT))) +1 FROM EMPLOYEES;
</code></pre>
I do not know why the '+1' in the end is needed to get the correct answer.

blocks|key|4140067|text|您可以使用:+TO_NUMBER(REPLACE('0349010330',0))|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4140068|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

You can use:
TO_NUMBER(REPLACE('0349010330',0))

blocks|key|2030216|text|HackerRank+Mysql解决方案https://www.hackerrank.com/challenges/the-blunder/problem|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2030217|SELECT+CEIL((AVG(SALARY))-(AVG(REPLACE(SALARY,'0',''))))+FROM+EMPLOYEES|code-block|syntax|javascript|2030218|entityMap|0|LINK|mutability|MUTABLE|url|https://www.hackerrank.com/challenges/the-blunder/problem^0|K|1L|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

HackerRank Mysql Solution <a href="https://www.hackerrank.com/challenges/the-blunder/problem" rel="nofollow noreferrer">https://www.hackerrank.com/challenges/the-blunder/problem</a>

<pre><code>SELECT CEIL((AVG(SALARY))-(AVG(REPLACE(SALARY,'0','')))) FROM EMPLOYEES
</code></pre>

blocks|key|4140173|text|https://www.hackerrank.com/challenges/the-blunder/problem|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4140174|对于Mysql，请在下面运行查询|4140175|select+ceil(Avg(Salary)+-+Avg(CAST(Replace(CAST(Salary+as+char(1000)),'0','')+as+unsigned)))+from+EMPLOYEES|code-block|syntax|javascript|4140176|entityMap|0|LINK|mutability|MUTABLE|url^0|0|1L|0|0|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@$A|S|B|T|1|U]]|C|$]]|$1|D|3|E|5|6|7|V|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|W|8|@]|9|@]|C|$I|J]]|$1|K|3|-4|5|6|7|X|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|4]]]]

<a href="https://www.hackerrank.com/challenges/the-blunder/problem" rel="nofollow noreferrer">https://www.hackerrank.com/challenges/the-blunder/problem</a>

For Mysql, Please run below query

<pre><code>select ceil(Avg(Salary) - Avg(CAST(Replace(CAST(Salary as char(1000)),'0','') as unsigned))) from EMPLOYEES
</code></pre>

blocks|key|1631954|text|这是答案|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1631955|替换(薪水，0)|1631956|在hackerrank..blunder问题中发现了类似的问题|1631957|从员工中选择ceil(avg(salary)-+avg(replace(salary，0)；|1631958|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|L|8|@]|9|@]|A|$]]|$1|F|3|G|5|6|7|M|8|@]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

Here is answer
replace(salary,0)
A question similar to this found in hackerrank..blunder problem
select ceil(avg(salary)- avg(replace(salary,0))) from employees;

blocks|key|5557736|text|我认为您不需要to_number(+replace(+to_char(x),+'0',+''+)+)，您可以简单地输入|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|5557737|5557738|+replace(x,+'0')|blockquote|5557739|5557740|5557741|并且铸件是自动施加的。此外，您不必指定0为空replace(x,+'0',+'')，因为默认情况下，如果不指定第一个值，replace()将删除第一个值。|5557742|entityMap^0|7|17|0|0|1|F|0|0|0|M|J|1O|9|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|S|8|@]|D|@]|E|$]]|$1|G|3|H|5|I|7|T|8|@$9|U|A|V|B|C]]|D|@]|E|$]]|$1|J|3|-4|5|6|7|W|8|@]|D|@]|E|$]]|$1|K|3|-4|5|6|7|X|8|@]|D|@]|E|$]]|$1|L|3|M|5|6|7|Y|8|@$9|Z|A|10|B|C]|$9|11|A|12|B|C]]|D|@]|E|$]]|$1|N|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|O|$]]

I think you do not need <code>to_number( replace( to_char(x), '0', '' ) )</code>
Instead you can simply type 

<blockquote>
 <code>replace(x, '0')</code>
</blockquote>

and the casting is applyed automaticaly.
Also, you do not have to specify 0 to be empty <code>replace(x, '0', '')</code> cause <code>replace()</code> by default removes the first value if you do not specify its alternative.

blocks|key|2030355|text|您可以在Oracle中使用REPLACE，但请记住将结果转换为number，因为REPLACE返回CHAR结果。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2030356|select+to_number(replace(1001,0,''))+from+dual|code-block|syntax|javascript|2030357|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use REPLACE in Oracle but remember to convert the result to number because REPLACE returns CHAR result.

<pre><code>select to_number(replace(1001,0,'')) from dual
</code></pre>

blocks|key|4140437|text|以下是使用MySQL解决Hackerrank问题的答案：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4140438|SELECT+round(avg(salary),0)-round(avg(replace(salary,'0','')),0)+from+EMPLOYEES;|code-block|syntax|javascript|4140439|您可以使用：|4140440|replace(Column_Name,'0','')|4140441|上面给出的查询从给定的整型输入中删除0|4140442|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Here is the answer using MySQL for Hackerrank problem:
<pre><code>SELECT round(avg(salary),0)-round(avg(replace(salary,'0','')),0) from EMPLOYEES;
</code></pre>
you can use:
<pre><code>replace(Column_Name,'0','')
</code></pre>
the above given query to remove 0 from the given integer type input

blocks|key|4140452|text|select+
++++avg(salary)+-+avg(convert(integer,+replace(salary,'0',+'')))+%2B+1+
from+employees|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4140453|这就是答案|unstyled|4140454|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>select 
 avg(salary) - avg(convert(integer, replace(salary,'0', ''))) + 1 
from employees
</code></pre>
This is the answer

blocks|key|1635486|text|这是在任意数字中删除0的答案。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1635487|replace('0349010330',+'0',+'')+|code-block|syntax|javascript|1635488|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is the answer for removing 0 in any number.
<pre><code>replace('0349010330', '0', '') 
</code></pre>

blocks|key|1635490|text|HackerRank解决方案https://www.hackerrank.com/challenges/the-blunder/problem|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1635491|在SQL+Server中|1635492|SELECT+CAST(CEILING+(AVG(CAST(SALARY+AS+float))+-+AVG(CAST(REPLACE(salary,+'0',+'')AS+float)+)+)+as+int)+FROM+EMPLOYEES;|style|CODE|1635493|这里，实际的平均工资是4046.75，错误计算的平均工资是1794.5，因此差值是2252.25，向上舍入时是2253.0，但是hackerrank解决方案希望它是int，所以我们需要再次将它转换回int。|1635494|entityMap|0|LINK|mutability|MUTABLE|url|https://www.hackerrank.com/challenges/the-blunder/problem^0|E|1L|0|0|0|0|3C|0|0^^$0|@$1|2|3|4|5|6|7|T|8|@]|9|@$A|U|B|V|1|W]]|C|$]]|$1|D|3|E|5|6|7|X|8|@]|9|@]|C|$]]|$1|F|3|G|5|6|7|Y|8|@$A|Z|B|10|H|I]]|9|@]|C|$]]|$1|J|3|K|5|6|7|11|8|@]|9|@]|C|$]]|$1|L|3|-4|5|6|7|12|8|@]|9|@]|C|$]]]|M|$N|$5|O|P|Q|C|$R|S]]]]

HackerRank Solution <a href="https://www.hackerrank.com/challenges/the-blunder/problem" rel="nofollow noreferrer">https://www.hackerrank.com/challenges/the-blunder/problem</a>
in SQL Server
<code>SELECT CAST(CEILING (AVG(CAST(SALARY AS float)) - AVG(CAST(REPLACE(salary, '0', '')AS float) ) ) as int) FROM EMPLOYEES;</code>
Here, the actual average salary comes out to be 4046.75
and miscalculated avg salary comes out as 1794.5
Hence the difference 2252.25, which when rounded up is 2253.0,
but the hackerrank solution expects it as int,
so we need to again cast it back to int.

How can I remove zeros (not just leading zeros, but zeros in every position) from a column containing Integers(numbers)?
For example : 0349010330 should become 349133

Removing zeros from number

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如何从包含整数(数字)的列中删除零(不仅是前导零，而且是每个位置的零)？例如: 0349010330应该变成349133

问从数字中删除零
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