在下面提到的情况下，如何有效地比较两个列表中的字符串：

Question

t_codes = ["11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-VM-ZRA-Operator",
             "11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-VM-ZRA-Admin",
             "11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-ZRA-User-VM-Admin",
             "11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-VM-ZRA-Operator",
             "11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator",
             "11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-VM-ZRA-Admin",
             "11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-ZRA-User-VM-Admin",
             "22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-VM-ZRA-Operator",
             "22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-VM-ZRA-Admin",
             "22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-ZRA-User-VM-Admin",
             "22-GLB-IaaS-PaaS-PROD-MSDP-CUSTOMER-IN-ZRA-User-VM-Admin",    
             "11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator"]

t_names = ["Outsite", "NewFm", "CUSTOMER-IN"]

上面提到的是我的初始输入列表。

我需要从t_codes创建2个列表，通过将t_names的每个元素与t_codes的每个元素进行匹配来创建-

列表1是

["11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator" , "11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator"] 

此列表包含不包含t_names中提到的任何字符串的所有元素

列表2是

["11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-VM-ZRA-Operator",
             "11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-VM-ZRA-Admin",
             "11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-ZRA-User-VM-Admin",
             "11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-VM-ZRA-Operator",           
             "11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-VM-ZRA-Admin",
             "11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-ZRA-User-VM-Admin",
             "22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-VM-ZRA-Operator",
             "22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-VM-ZRA-Admin",
             "22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-ZRA-User-VM-Admin",
             "22-GLB-IaaS-PaaS-PROD-MSDP-CUSTOMER-IN-ZRA-User-VM-Admin" ]

此列表包含来自t_names的Outsite、NewFm、CUSTOMER-IN字符串。

我尝试的是：

does_contain = []
doesnt_contain = []
for tool in t_names:
    for team in t_codes:         
        if bool(re.search(tool, team)):
            does_contain.append(team)
        else:
            doesnt_contain.append(team)
            
print(does_contain)
print("-------------")
print(doesnt_contain)

由于显而易见的原因，这并没有给我提供预期的输出。请帮帮忙。

Answer 1

国际海事组织你要找的是any(...)

list1, list2 = [[], []]
for t_code in t_codes:
    if any(t_name in t_code for t_name in t_names):
        list1.append(t_code)
    else:
        list2.append(t_code)

print(list1)
print(list2)

对于给定的输入，这会产生以下结果：

['11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-VM-ZRA-Operator', '11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-VM-ZRA-Admin', '11-XXX-Yaas-ZaaS-XXX-ZZZZ-Outsite-ZRA-User-VM-Admin', '11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-VM-ZRA-Operator', '11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-VM-ZRA-Admin', '11-XXX-Yaas-ZaaS-XXX-ZZZZ-NewFm-ZRA-User-VM-Admin', '22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-VM-ZRA-Operator', '22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-VM-ZRA-Admin', '22-GLB-IaaS-PaaS-PROD-MSDP-Outsite-ZRA-User-VM-Admin', '22-GLB-IaaS-PaaS-PROD-MSDP-CUSTOMER-IN-ZRA-User-VM-Admin']
['11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator', '11-XXX-Yaas-ZaaS-XXX-ZZZZ-VM-ZRA-Operator']

Answer 2

您应该将列表转换为set类型。set类型本身就有这种操作。