我有php函数来获取这个和下周的日期。除了周四,一切都很好--周四的产出是空的。
下面是我的代码:
$pondeli1 = date( 'd.m.Y', strtotime( 'monday this week' ) );
$utery1 = date( 'd.m.Y', strtotime( 'tuesday this week' ) );
$streda1 = date( 'd.m.Y', strtotime( 'wednesday this week' ) );
$ctrvtek1 = date( 'd.m.Y', strtotime( 'thursday this week' ) );
$patek1 = date( 'd.m.Y', strtotime( 'friday this week' ) );
$pondeli2 = date( 'd.m.Y', strtotime( 'monday next week' ) );
$utery2 = date( 'd.m.Y', strtotime( 'tuesday next week' ) );
$streda2 = date( 'd.m.Y', strtotime( 'wednesday next week' ) );
$ctrvtek2 = date( 'd.m.Y', strtotime( 'thursday next week' ) );
$patek2 = date( 'd.m.Y', strtotime( 'friday next week' ) );带有“下周四”的行不会返回任何内容...
问题出在哪里?
发布于 2016-02-19 18:56:53
试着使用
$ctrvtek2 =strtotime("next Thursday",$ctrvtek1);https://stackoverflow.com/questions/35503472
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