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社区首页 >问答首页 >C++中的Java Iterator等价物?(带代码)

C++中的Java Iterator等价物?(带代码)
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Stack Overflow用户
提问于 2011-06-05 18:33:53
回答 1查看 1.1K关注 0票数 5

大家好。我的一个朋友为我写了一些Java代码,我可以很容易地将它转换成C++,但我非常好奇C++中的Java迭代器的等价物。下面是代码,我很可能希望将数据返回到一个向量中。任何帮助我们都将不胜感激

代码语言:javascript
复制
public class RLEIterator
extends RegionIterator
{
    public int reg = 0;
    public int mode = 0;
    public int skip = 0;
        // mode is the number of IDs that are valid still (count down)
        // skip is used after we run out of mode IDs, and move forward
        //   The goal is, to always have a valid 'hasNext' state, after
        // an ID is read via 'next'. Thus, the initial search, and then
        // the reading forward if mode == 0, after the ID is found.
    public int i;

    public RLEIterator()
    {
        // Need to set up the skip of an initial part, so we can
        // correctly handle there not being anything, despite there
        // being data encoded.

        int comp;
        i = 0;

        while ((mode == 0) && (i<nearRLE.length))
        {
            // set up the next code
            comp = ((int)nearRLE[i]) & 0xff;

            if ((comp > 0) && (comp <= 0x3e))
            {
                // skip forward by comp;
                reg += comp;
                i++;
                mode = 0; // have to keep on reading
            }
            else if (comp == 0x3f)
            {
                // skip forward by the following 16 bit word;
                // second byte is hi-byte of the word
                reg += ((int)nearRLE[i+1]) & 0xff;
                reg += (((int)nearRLE[i+2]) & 0xff) << 8;

                i+=3;
            }
            else if (comp == 0xff)
            {
                // include the following WORD of regions
                mode = ((int)nearRLE[i+1]) & 0xff;
                mode += (((int)nearRLE[i+2]) & 0xff) << 8;
                i += 3;
            }
            else if ((comp >= 0xc0) && (comp <= 0xfe))
            {
                // comp - 0xc0 regions are nearby
                mode = comp - 0xc0;  // +1 perhaps?
                i++;
            }
            else if ((comp >= 0x40) && (comp <= 0x7f))
            {
                // skip bits 3-5 IDs and then include bits 0-2
                reg += (comp & 0x38) >> 3;
                mode = (comp & 0x7);
                i++;
            }
            else if ((comp >= 0x80) && (comp <= 0xbf))
            {
                // include IDs bits 3-5, then skip bits 0-2
                mode = (comp & 0x38) >> 3;
                skip = (comp & 0x7);
                i++;
            }
        }
    }

    public boolean hasNext()
    {
        // not at the end of the RLE, and not currently processing a
        // directive. (mode)
        return (mode > 0);
    }

    public int next()
    {
        int ret = -1;
        int comp;

        // sanity check first. Shouldn't truthfully get called if mode
        // isn't >0
        if (mode <= 0)
            return -1;

        ret = reg;
        reg++;
        mode--;

        if (mode == 0)
        {
            // skip forward
            reg += skip;
            skip = 0;

            while ((mode == 0) && (i<nearRLE.length))
            {
                // set up the next code
                comp = ((int)nearRLE[i]) & 0xff;

                if ((comp > 0) && (comp <= 0x3e))
                {
                    // skip forward by comp;
                    reg += comp;
                    i++;
                    mode = 0; // have to keep on reading
                }
                else if (comp == 0x3f)
                {
                    // skip forward by the following 16 bit word;
                    // second byte is hi-byte of the word
                    reg += ((int)nearRLE[i+1]) & 0xff;
                    reg += (((int)nearRLE[i+2]) & 0xff) << 8;

                    i+=3;
                }
                else if (comp == 0xff)
                {
                    // include the following WORD of regions
                    mode = ((int)nearRLE[i+1]) & 0xff;
                    mode += (((int)nearRLE[i+2]) & 0xff) << 8;
                    i += 3;
                }
                else if ((comp >= 0xc0) && (comp <= 0xfe))
                {
                    // comp - 0xc0 regions are nearby
                    mode = comp - 0xc0;  // +1 perhaps?
                    i++;
                }
                else if ((comp >= 0x40) && (comp <= 0x7f))
                {
                    // skip bits 3-5 IDs and then include bits 0-2
                    reg += (comp & 0x38) >> 3;
                    mode = (comp & 0x7);
                    i++;
                }
                else if ((comp >= 0x80) && (comp <= 0xbf))
                {
                    // include IDs bits 3-5, then skip bits 0-2
                    mode = (comp & 0x38) >> 3;
                    skip = (comp & 0x7);
                    i++;
                }
            }
        }

        return ret;
    }
}

同样,任何关于如何将其融入C++中的单个函数(如果可能)的帮助都将是非常棒的。谢谢!

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2011-06-05 20:33:56

你对C++迭代器有多熟悉?它们被设计成看起来非常像指针,所以给定一个迭代器it

代码语言:javascript
复制
++it

将递增迭代器(跳到下一个元素)

代码语言:javascript
复制
*it

将取消对迭代器的引用(返回对其指向的元素的引用)

代码语言:javascript
复制
--it

将(如果定义了的话)递减迭代器(返回到前一个元素)

C++迭代器通常对它们所操作的容器一无所知。特别是,检查序列中是否还有更多元素的方法不是在迭代器上调用HasNext,而是将其与已知指向序列末尾的迭代器进行比较。(或者,严格地说,将其与指向序列末尾的元素进行比较。)

除此之外,迭代器还需要定义一些typedefs和其他辅助内容来帮助编译器对迭代器的功能进行分类和理解。

定义迭代器的最简单方法是使用Boost.Iterator库的iterator_facade类,它为您实现了几乎所有的管道。这个库有很好的文档,包括一个描述如何定义你自己的迭代器类型的教程。

如果使用Boost是一种选择,那么您绝对应该使用它。另外,标准库的std::iterator也有一些帮助(但是,值得注意的是,它不是强制性的--迭代器可以完全有效地定义,而不需要从这个类派生)。

很抱歉,我没有写出完整的示例,但我现在有点赶时间。(而且,如果您能够使用Boost,那么从头开始定义示例迭代器的麻烦将是浪费时间)。希望上面的内容足以让你入门。

票数 4
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/6242353

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